Answer:
The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h
Step-by-step explanation:
At noon the location of Lan = 300 km north of Makenna
Lan's direction = South
Lan's speed = 60 km/h
Makenna's direction and speed = West at 75 km/h
The distance Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km
The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km
The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km
Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.
By Pythagoras' theorem, we have;
s² = x² + y²
The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61
ds²/dt = dx²/dt + dy²/dt
2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt
2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900
ds/dt = 900/(2×30·√61) ≈ 1.92
The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h
Area is base x height over 2
64 x 7.3 = 467.2
467.2/2 = 233.6
the area is 233.6m^2
7. is C 3/50
8. is H 2/3
9. is C 2/3
10. is B slope 4 y intercept -2
11. is -1/4 slope
12. is 1/5 slope
13. is -2/3 slope
14. is 6 is the slope
15. is y=5/3x+5
16. is y=1/2x-3
17. is y=-3/5x+4
18. is y=3/2x-3 :)
Answer:
Thousand - 8,501,000
Hundred Thousand - 8,500,000
Million - 9,000,000
Step-by-step explanation:
