Since he’s already at -15, if he writes a check for 7 then he’s subtracting more from his account.
So, -15-7=-22
It’s volume / designation
9514 1404 393
Answer:
(5, 6) is (h, k)
Step-by-step explanation:
Vertex form is an instance of the transformation of parent function f(x) = x². It is vertically scaled by a factor of 'a', and translated so the vertex is point (h, k). That is, the transformed vertex is h units right and k units up from that of the parent function (0, 0).
Parent:
f(x) = x^2
Transformed:
f(x) = a(x -h)^2 +k
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When you compare the form to your specific instance, you need to pay attention to what it is that you're comparing. As the attachment shows, ...
- a = 2
- -h = -5 ⇒ h = 5
- k = 6
Hence the vertex is (h, k) = (5, 6). The second attachment shows this on a graph.
Answer: ![(-\infty, -4]](https://tex.z-dn.net/?f=%28-%5Cinfty%2C%20-4%5D)
Curved parenthesis at negative infinity
Square bracket at -4
====================================================
Work Shown:

The last inequality shown above is the same as saying 
Converting this to interval notation leads to the final answer of ![(-\infty , -4]](https://tex.z-dn.net/?f=%28-%5Cinfty%20%2C%20-4%5D)
Note the use of a square bracket at -4 to include this endpoint. We can never include either infinity, so we always use a parenthesis for either infinity.