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3 years ago

Someone help me asap

Mathematics

2 answers:

dem82 [27]3 years ago

3 0

1. 10

2(3 + 2)

2(5)

2. $631

59 + 13(44)

59 + 572

631

3. a number decreased by 4

jeyben [28]3 years ago

3 0

1. 10
2.631
3. a number decreased by 4

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The measure of an angle exceeds 3 times its supplement by 4. Find the measure of the angles.

Dafna11 [192]

X=3y+4, y=y
x+y=180, 3y+4+y=180, 4y+4=180
4y+4=180
4y=176
y=44
x=3(44)+4, x=132+4, x=136

(I am not a very good artist in this case:)

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2 years ago

Please help me with my homework

Alona [7]

so for A it is 16 times as large because the area is 3*3 which is 9 but since it is a triangle the area is halved and is 4.5 and divide 72 by 4.5 which gives us 16

then for b I believe that the scale factor is 4

and for C it is asking for the bottom side of the scaled copy not of triangle A and 4*3=12 so the bottom is 12

ok now its complete =)

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3 years ago

Determine the slope of the linear function. Y= 1/5 x + 6

Novay_Z [31]

D. 1/5

Reason: it’s always the first number in the equation

7 0

3 years ago

Read 2 more answers

Nancy's garden has the dimensions shown 4 1/2 yard<br><br> 3 3/4 yd . She need find the area

Marina86 [1]

Answer:

The area of Nancy's garden is $16\frac{7}{8}\ yd^{2}$

Step-by-step explanation:

I assume that the Nancy's garden is a rectangle shape

To find the area first convert mixed number to an improper fraction

$4\frac{1}{2}\ yd=\frac{4*2+1}{2}=\frac{9}{2}\ yd$

$3\frac{3}{4}\ yd=\frac{3*4+3}{4}=\frac{15}{4}\ yd$

Therefore

The area is equal to

$A=\frac{9}{2}*\frac{15}{4}=\frac{135}{8}\ yd^{2}$

convert to mixed number

$\frac{135}{8}\ yd^{2=\frac{128}{8}+\frac{7}{8}=16\frac{7}{8}\ yd^{2}$

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3 years ago

Cual es la derivada de ()=√x sin

fgiga [73]

Answer:

$f(x) =\sqrt{x} sin (x)$

And on this case we can use the product rule for a derivate given by:

$\frac{d}{dx} (f(x)* g(x)) = f'(x) g(x) +f(x) g'(x)$

Where $f(x) =\sqrt{x}$ and $g(x) =sin (x)$

And replacing we have this:

$f'(x)= \frac{1}{2\sqrt{x}} sin (x) + \sqrt{x}cos(x)$

Step-by-step explanation:

We assume that the function of interest is:

$f(x) =\sqrt{x} sin (x)$

And on this case we can use the product rule for a derivate given by:

$\frac{d}{dx} (f(x)* g(x)) = f'(x) g(x) +f(x) g'(x)$

Where $f(x) =\sqrt{x}$ and $g(x) =sin (x)$

And replacing we have this:

$f'(x)= \frac{1}{2\sqrt{x}} sin (x) + \sqrt{x}cos(x)$

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2 years ago