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aleksandrvk [35]
3 years ago
15

I need answers ASAP! Thanks!

Mathematics
1 answer:
Daniel [21]3 years ago
3 0

Step-by-step explanation:

43. P, U

44. 7

53. Airplanes can be traveling on different planes, one plane above the other. Cars on the same intersection are on the same plane.

55

a. You can choose (4 * 3 * 2)/(3 * 2) = 4 groups of 3 points in which order does not matter.

One of those combinations does not have K, so 3 combinations of the 4 have K.

p = 3/4

b. p = 1 since any three points are always coplanar.

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Find the perimeter and are of the trapezoid
lara31 [8.8K]

Answer:

47.7ft

Step-by-step explanation:

12.8ft+6.2ft+13.9ft+15.5ft=47.7ft

8 0
2 years ago
- 2 + 0.8) ÷ (- 1.3) =<br><img src="https://tex.z-dn.net/?f=%20%28%20-%202%20%2B%200.8%29%20%5Cdiv%20%28%201%7D%5E%7B2%7D%20%20-
Nookie1986 [14]
(-2 + 0.8) ÷ (1²-1.3) =

(-1.2) ÷ (1-1.3)

(-1.2) ÷ (-0.3)

= 4
6 0
3 years ago
WILL MARK BRAINLIEST!!!!!!!!
SVETLANKA909090 [29]

Data:

15 16 14 15 19 17

n=6 points

sum is 96

mean is 96/6 = 16

Now we look at the absolute deviations, each of which is the absolute value of a score minus the mean, basically the distance of the score to the mean .

Scores   15 16 14 15 19 17

AbsDev    1  0  2  1    3  1

The sum of the absolute deviations is 8 and there are six of them so the

Mean Absolute Deviation = 8/6 = 4/3

Answer: 2.    8/6

7 0
3 years ago
After a rotation of 90° about the origin, the coordinates of the vertices of the image of a triangle are A'(6, 3), B'(-2, 1),
Rasek [7]

Answer:

<em>A</em>(-3, 6), <em>B</em>(-1, -2), <em>C</em>(-7, 1)

Step-by-step explanation:

To the pre-image after a 270°-counterclockwise rotation [90°-clockwise rotation], just reverse it by doing a 270°-clockwise rotation [90°-counterclockwise rotation]:

Extended Rotation Rules

  • 270°-clockwise rotation [90°-counterclockwise rotation] >> (x, y) → (-y, x)
  • 270°-counterclockwise rotation [90°-clockwise rotation] >> (x, y) → (y, -x)
  • 180°-rotation >> (x, y) → (-x, -y)

So, perform your rotation:

270°-clockwise rotation [90°-counterclockwise rotation] → <em>C</em><em>'</em>[1, 7] was originally at <em>C</em>[-7, 1]

→ <em>B'</em>[-2, 1] was originally at <em>B</em>[-1, -2]

→ <em>A</em><em>'</em>[6, 3] was originally at <em>A</em>[-3, 6]

I am joyous to assist you anytime.

3 0
3 years ago
Read 2 more answers
Which polynomial correctly combines the like terms and puts the given polynomial in standard form? -5x^3y^3+8x^4y^2-xy^5-2x^2y^4
victus00 [196]

Given:

The polynomial is:

-5x^3y^3+8x^4y^2-xy^5-2x^2y^4+8x^6+3x^2y^4-6xy^5

To find:

The simplified form of the given polynomial in standard form.

Solution:

We have,

-5x^3y^3+8x^4y^2-xy^5-2x^2y^4+8x^6+3x^2y^4-6xy^5

Combining the like terms, we get

=-5x^3y^3+8x^4y^2+(-2x^2y^4+3x^2y^4)+8x^6+(-xy^5-6xy^5)

=-5x^3y^3+8x^4y^2+x^2y^4+8x^6-7xy^5

Now, rewrite this polynomial in standard form.

=8x^6+8x^4y^2-5x^3y^3+x^2y^4-7xy^5

Therefore, the required polynomial in standard form is 8x^6+8x^4y^2-5x^3y^3+x^2y^4-7xy^5.

8 0
3 years ago
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