Answer:
Explanation:
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Answer:
#include<iostream>//library inclusion
using namespace std;
int main()
{
int userInput;
do//start of do while loop
{
cout << "Enter a number less than a 100" << endl;
cin >> userInput;
if (userInput < 100) //condition
{
cout << "YOu entered less than a hundred: " << userInput << endl;
}
else
{
cout << "your number is greater than 100" << endl;
}
} while (userInput > 100);//condition for do while
return 0;//termination of int main
}
Explanation:
The program has been commented for you. The do-while loop enters the first loop regardless of the condition. Then after the first iteration, it checks for the condition. If the condition is being met, it will iterate through, again. Otherwise it will break out of the loop and land on the "return 0;" line. Which also happens to be the termination of the program in this case. The if-else condition is used for the user to see when prompted.
Answer:
Explanation:
The following code is written in Java. It is a method that calculates the square root of a number as requested. The method first checks with an IF statement if the parameter value is a positive number and then calculates the square root and prints it to the screen. Otherwise, it prints Number must not be negative. A test case has been provided in the main method and the output can be seen in the attached image below.
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.print("Enter a number of type double to calculate square root:");
double num = in.nextDouble();
rootPositive(num);
}
public static void rootPositive(double num) {
if (num > 0) {
System.out.println(Math.sqrt(num));
} else {
System.out.println("Number must not be negative.");
}
}
}
Answer:
same as above....................