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2 years ago

PLEASEEEE I NEED HELP!!!! Find k in the following arithmetic sequence: 4k-k^2, 3k, k

1 answer:

3 0

3k - (k-2) = (k-2) - (k+7) 3k = (k-2) - (k+7) + (k-2) 3k = 2(k-2) - (k+7) 3k = 2k - 4 - k - 7 3k = k - 11 2k = -11
k = -5.5

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Justin needs to earn a score of more than 80 on his next math test to earn a B for the semester. Which inequality shows the grad

zvonat [6]

Answer:

Step-by-step explanation:

Justin's score has to be greater than 80. the appropriate inequality sign is >

Note that

> means greater than

< means less than

≥ means greater than or equal to

≤ less than or equal to

On the number line, since the score has to be greater than 80, the line would start from 80 and end on 95

> or < is represented by unfilled circle

≤ or ≥ is represented by filled circle

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2 years ago

What is the slope of the line passing through the points (7, 10) and (5, 16) ?<br> Thank you

butalik [34]

Answer:

m=-3

Step-by-step explanation:

m=y2-y1/x2-x1

m=16-10/5-7

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1 year ago

Please help me on this question.

saw5 [17]

Answer:

answer is option D (56)

Step-by-step explanation:

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6 0

2 years ago

Read 2 more answers

Find the perimeter of pentagon STUVW WITH VERTICES S(0,0) T(3,-2) U(2,-5) V(-2,-5) W(-3,-2)

andrew11 [14]

Use the distance formula.

$\sqrt{( x_{2} - x_{1} )^2 + (y_{2} - y_{1})^2}$

Points S and W.
$\sqrt{(3)^2 + (2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points S and T
$\sqrt{(3 - 0)^2 + (-2 - 0)^2}$

$\sqrt{(3)^2 + (-2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points T and U
$\sqrt{(3 - 2)^2 + (-2 + 5)^2}$

$\sqrt{(1)^2 + (3)^2}$

$\sqrt{1+9}$

$\sqrt{10}$

~3.1

Points U and V
$\sqrt{(2+2)^2 + (-5 + 5)^2}$

$\sqrt{(4)^2 + (0)^2}$

$\sqrt{16}$

~4

Points V and W
$\sqrt{(-2+3)^2 + (-5 + 2)^2}$

$\sqrt{(1)^2 + (-3)^2}$

$\sqrt{2+9}$

$\sqrt{11}$

~3.3

Add all these together.

3.3 + 3.1 + 4 + 3.1 + 3.6
≈17

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2 years ago

What is equivalent to k/2

Mazyrski [523]

Answer:

k x 1/2

Step-by-step explanation:

because k x 1/2 = k/2

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2 years ago