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sergejj [24]
3 years ago
5

PLEASEEEE I NEED HELP!!!! Find k in the following arithmetic sequence: 4k-k^2, 3k, k

Mathematics
1 answer:
LenaWriter [7]3 years ago
3 0
 3k - (k-2) = (k-2) - (k+7) 3k = (k-2) - (k+7) + (k-2) 3k = 2(k-2) - (k+7) 3k = 2k - 4 - k - 7 3k = k - 11 2k = -11 
k = -5.5
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Given: sin(18m-12)=cos(7m+2), find the value of m.
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Answer:

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Step-by-step explanation:

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Multiply both sides by -1:

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Split into two equations:

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Take the inverse cosine of both sides:

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Subtract 2 from both sides:

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or sin(12 - 18 m) = 0

Divide both sides by 7:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or sin(12 - 18 m) = 0

Take the inverse sine of both sides:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

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Subtract 12 from both sides:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or -18 m = π n_2 - 12 for n_2 element Z

Divide both sides by -18:

Answer: m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or m = 2/3 - (π n_2)/18 for n_2 element Z

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