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Naya [18.7K]
3 years ago
12

If (3,4) is reflected across the x-axis what are the new coordinates​

Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
8 0

Answer:

The answer is (-3, 4).

Step-by-step explanation:

(3, 4) is located in Quadrant I, which is (+, +). Since you're reflecting the point across the x-axis, you'll be in Quadrant IV, which is (-, +). The point will now be (-3, 4).

I hope this helped! :-)

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Kaitlyn can run 1.35 miles in 12 minutes. What is her running speed per hour?
vazorg [7]

Answer:

the answer is 6.75

Step-by-step explanation:

12 x 5 = 60 60 = 1 hour so 1.35 x 5 = 6.75

7 0
3 years ago
Need help 1-4 I'll appreciate it
uranmaximum [27]
For Q1 add 135 and 45 together. If it comes out to be 180 which it does the angles are supplementary. In Q2 add 23 and 67 together and if it comes out to 90 it is complementary, but if it doesn't it is neither. In Q3 take 3x+45=180 subtract 45 on both sides so you get 3x=135 then divide by 3 to get X. Your answer should be 45. For Q4 look that exact question up and find a good answer for it. Hope this could help
6 0
3 years ago
To construct an interval estimate for the difference between the means of two populations when the standard deviations of the tw
kobusy [5.1K]

Answer:

C. (n₁ + n₂ - 2) degrees of freedom

Step-by-step explanation:

The t-test for difference between two mean when variance are equal is:

t=\dfrac{\bar{x}_1-\bar{x}_2}{s\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

where ,

\bar{x}_1 = Mean of Sample 1

\bar{x}_2 = Mean of Sample 2

s = standard deviation

n_1 = size of Sample 1

n_2 = size of Sample 2

 and t is Student's t-test with (n₁ + n₂ - 2) degrees of freedom.

5 0
3 years ago
Two pools are being filled with water. To start, the first pool had 1850 liters of water and the second pool had 1334 liters of
prohojiy [21]

Answer:

a)Total amount of water in pool 1 after x minutes = 1850+27x

Total amount of water in pool 2 after x minutes = 1334+39x

b) an equation to show when the two pools would have the same amount of water is 1850+27x= 1334+39x

Step-by-step explanation:

First Pool :

Initial amount of water in Pool = 1850 liters

Water is being added to the first pool at a rate of 27 liters per minute.

Amount of water added after x minutes = 27x

So, Total amount of water after x minutes = 1850+27x

Second Pool:

Initial amount of water in Pool = 1334 liters

Water is being added to the first pool at a rate of 39 liters per minute.

Amount of water added after x minutes = 39x

So, Total amount of water after x minutes = 1334+39x

Now to find  an equation to show when the two pools would have the same amount of water.

1850+27x= 1334+39x

1850-1334=39x-27x

516=12x

\frac{516}{12}=x

43 =x

Hence

a)Total amount of water in pool 1 after x minutes = 1850+27x

Total amount of water in pool 2 after x minutes = 1334+39x

b) an equation to show when the two pools would have the same amount of water is 1850+27x= 1334+39x

5 0
3 years ago
Solve -4/5 divided by -2/3 then explain how you got your answer!!!! HELP ME WITH THISSS
harina [27]

Your answer will be -1 2/10, or -1 1/5 if you're looking for a simplified answer. My method is called KCF, or Keep Change Flip. First, you don't have to do anything with the -4/5. Next, you would want to change the division to multiplication. It is possible to just divide across, but changing it to multiplication is way easier and will save time. After that, you would switch -2/3 to -3/2. FLIPPING THE SECOND FRACTION DOES NOT MEAN THE NEGATIVE TURNS INTO A POSITIVE. Your answer would be 12/10, but we aren't done just yet. 10 goes into 12 once, now we have 1 2/10 left over. If you simplify you will get 1 1/5. So there you have it! I answered you question as best as I could and I hope this was helpful.

3 0
3 years ago
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