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Tema [17]
2 years ago
10

A construction team gives an estimate of three months to repave a large stretch of a very busy road with their core crew of 9 pe

ople. The government responds that it is too much of an inconvenience to have this busy road obstructed for three months, so the job must be completed in one month. If the relationship between construction time and crew members is inversely proportional, how many crew members does the construction team need if they are to complete the job in one month
Mathematics
1 answer:
Licemer1 [7]2 years ago
6 0

Answer:

27

Step-by-step explanation:

9 crew members complete a job in 3 months

Number of crew members is inversely proportion to construction time :

Let :

Crew members = m

Construction time = t

m α 1 /t

m = k/t

m = 9 ; t = 3

9 = k /3

k = 27

If t = 1 (one month)

m =?

m = k/t

m = 27 / 1

Hence;

m = 27 * 1

m = 27 workers

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at a golf course, a worker placed 216 golf balls equally into 9 buckets. what is the ratio of golf balls to buckets?
ankoles [38]
The ratio is 216:9, which can be simplified to 72:3, which can be simplified to 34:1. This can also be written as a fraction (34/1). It means there are 34 golf balls for every one bucket.
4 0
3 years ago
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How do you solve 2/7m -1/7 = 3/14
Mars2501 [29]

the only thing you need to do is separate m:

2/7m= 3/14 + 1/7

2/7m= 5/14

m= (5/14)/(2/7)

m= 5/14 × 7/2

m= 35/28

m= 5/4

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What is the domain of f(6)=1
makkiz [27]
Six is the domain, while 1 is the codomain.
4 0
3 years ago
Help me please, need this done now.
Nikolay [14]

simplifying \frac{\sqrt{4}}{\sqrt[3]{4}} we get 4^{\frac{1}{6}}

Option B is correct.

Step-by-step explanation:

We need to simplify: \frac{\sqrt{4}}{\sqrt[3]{4}}

Solving:

\frac{\sqrt{4}}{\sqrt[3]{4}}

We know that √ = 1/2 and ∛=1/3

\frac{4^{\frac{1}{2}}}{4^{\frac{1}{3}}}

Applying exponent rule: \frac{x^a}{x^b}=x^{a-b}

=4^{\frac{1}{2}-\frac{1}{3}}\\=4^{\frac{3-2}{6}}\\=4^{\frac{1}{6}}

So, simplifying \frac{\sqrt{4}}{\sqrt[3]{4}} we get 4^{\frac{1}{6}}

Option B is correct.

Keywords: Solving Exponents  

Learn more about Solving Exponents at:

  • brainly.com/question/13174260
  • brainly.com/question/13174254
  • brainly.com/question/13174259

#learnwithBrainly

6 0
3 years ago
Suppose that J and K are points on the number line.
rodikova [14]

Answer:

-7, -27

Step-by-step explanation:

J is at -17. K is 10 units from J.

Start at point J, -17:

a) If you go 10 units to the right, you end up at -17 + 10 = -7

b) If you go 10 units to the left, you end up at -17 - 10 = -27

J can be at -7 or at -27

Answer: -7, -27

8 0
3 years ago
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