Answer:
1×1÷11. 5×3=15. 7×7=49 3×5=15 I'm not really sure but is there's anything else
Answer:
1. VW = 22
2. x = 87
Step-by-step explanation:
Question 1:
SU = 11 (given)
SU = ½(VW) => midsegment theorem
11 = ½(VW) => Substitution
Multiply both sides by 2
2*11 = VW
VW = 22
Question 2:
UV = x + 13
RT = x - 37
RT = ½(UV) => Midsegment Theorem
x - 37 = ½(x + 13) => Substitution
Multiply both sides by 2
2(x - 37) = x + 13
2x - 74 = x + 13
2x - 74 + 74 = x + 13 + 74
2x = x + 87
2x - x = x + 87 - x
x = 87
The answer is -1/64, i hope its helps
I guess your are selecting them without replacement, if so:
a) P(picking one defective) = 3/12
P(picking a 2nd defective) = 2/11
P(picking a 3rd defective) = 1/10
P(1 and 2 and 3 defective) = 3/12 x 2/11 x 1/10 = 1/220 = 0.0045
b) None defective: P( Non Defective) = 9/12 (follow Same logic):
9/12 x 8/11 x 7/10 = 21/55 = 0.38
Second method using combination:
a) ³C₃ / ¹²C₃ = 1/220 0.0045
B) ⁹C3 / ¹²C³ = 21/55 = 0.38
Answer: 6.7
Have a good day :D
