The correct answer that would best fit the given statement above would be the third option. <span>In a genome-wide expression study using a DNA microarray assay, each well is used to detect the expression of a specific gene by a cell. Hope this answers your question. Have a great day!</span>
Answer:
27 genotypes and 8 phenotypes
Explanation:
Supposing that the genotypes of both of the parents are AaBbDd (A, B and D are dominant over a, b and d). After completing the Punnett square, you can predict the following offspring:
I add an image where you can see all the 27 genotypes and frequencies.
Finally, all the 8 phenotypes with the following frequencies:
27/64 A-B-D-
9/64 A-B-dd
9/64 A-bbD-
9/64 aaB-D-
3/64 A-bbdd
3/64 aaB-dd
3/64 aabbD-
<u>1/64 aabbdd </u>
Total 64/64
Note: when a phenotype is A-, it means that it came from either genotype, AA or Aa. The same applies to B- (BB or Bb) and D- (DD or Dd)
Answer:
It is a true example of natural selection.
Explanation:
The dark colour mice lives in the dark soil of southeastern United States in large number as compared to other colour mice because this colour helps them to hide themselves from their predators in that dark soil while on the other hand, on light beaches of Florida light colour mice lives because this light colour also helps these mice in hiding from their enemy animals which is a true example of natural selection because dark colour mice can't survive in light colour beaches dude easily seen by their enemies and reduces its population by eating them.
There is a difference between the stem of these two plants because Ranunculus is dicot and Zea mays is a monocot. <span>Zea mays does not have a vascular cambium and has scattered vascular bundles composed of xylem and phloem tissue. On the other hand, Ranunculus has its vascular bundles in a ring arrangement and ground tissue is differentiated hypodermis, cortex, endodermis, pericycle and pith (there is no differentiation in Zea mays).</span>
