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kvasek [131]
3 years ago
10

Mike and steve have wallets with 5$ and 10$ bills. If together they have 20 bills, and in total 135$, how many 5$ and 10$ do the

y have" , you dont have to solve it , just put it in system of equation form please!
Mathematics
1 answer:
Brut [27]3 years ago
7 0
Y+x=20 this is the number of bills
5x+10y=135 this is the amount of money

X is the 5 dollar bills and y is the 10 dollar bills. 

If you put this into a graphing calculator it would give you your answer (or answers)
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M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{4}(12+7+13+11)\\\\\\M=\dfrac{43}{4}\\\\\\M=10.75\\\\\\s=\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2\\\\\\s=\dfrac{1}{3}((12-10.75)^2+(7-10.75)^2+(13-10.75)^2+(11-10.75)^2)\\\\\\s=\dfrac{20.75}{3}\\\\\\s=6.92\\\\\\

We have to calculate a 80% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=10.75.

The sample size is N=4.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.63}{\sqrt{4}}=\dfrac{2.63}{2}=1.315

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