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SpyIntel [72]
3 years ago
12

Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.

Mathematics
1 answer:
astra-53 [7]3 years ago
7 0

Answer:

\frac{dy}{dx}=\frac{1}{2(x-4)}

Step-by-step explanation:

We are given that a function  

y=ln(x-4)^{\frac{1}{2}}

We have to find the derivative of the function

y=\frac{1}{2}ln(x-4)

By using lna^b=blna

Differentiate w.r.t x

\frac{dy}{dx}=\frac{1}{2}\times \frac{1}{x-4}

By using formula

\frac{d(lnx)}{dx}=\frac{1}{x}

\frac{dy}{dx}=\frac{1}{2(x-4)}

Hence, the derivative of function

\frac{dy}{dx}=\frac{1}{2(x-4)}

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(32/8)-18+4
4-18+4
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5 0
3 years ago
Factor Completely.<br> 12k^2-16k-60
faltersainse [42]

Answer:

4(k - 3)(3k + 5)

Step-by-step explanation:

Given

12k² - 16k - 60 ← factor out 4 from each term

= 4(3k² - 4k - 15) ← factor the quadratic

Consider the factors of the product of the coefficient of the k² term and the constant term which sum to give the coefficient of the k term

product = 3 × - 15 = - 45 , sum = - 4

Factors are - 9 and + 5

Use these factors to split the middle term

3k² - 9k + 5k - 15 → ( factor the first/second and third/fourth terms

= 3k(k - 3) + 5(k - 3) ← factor out (k - 3)

= (k - 3)(3k + 5)

Hence

12k² - 16k - 60 = 4(k - 3)(3k + 5) ← in factored form

8 0
3 years ago
Read 2 more answers
24. What are the x and y intercepts of the following
Mila [183]

Answer:

C

A. X-intercept (6,0) and y-intercept (0,-8) wrong

B. x-intercept (-8,0) and y-intercept (0,6)wrong

C. x-intercept (4,0) and y-intercept (0,-3) correct

D. x-intercept (-3,0) and y-intercept (0,4) wrong

3 0
3 years ago
A random sample of 85 group leaders, supervisors, and similar personnel revealed that a person spent an average 6.5 years on the
strojnjashka [21]

Answer:

<em>95% of confidence interval for the Population</em>

<em>( 6.1386 , 6.8614)</em>

Step-by-step explanation:

<u><em>Step( i ):-</em></u>

<em>Given random sample size 'n' =85</em>

<em>Mean of the sample size x⁻ = 6.5 years</em>

<em>Standard deviation of Population = 1.7 years</em>

<em>Level of significance = 0.95 or 0.05</em>

<u><em>Step(ii):-</em></u>

<em>95% of confidence interval for the Population is determined by</em>

<em></em>(x^{-} - Z_{0.05} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.05} \frac{S.D}{\sqrt{n} })<em></em>

<em></em>(6.5 - 1.96\frac{1.7}{\sqrt{85} } , 6.5 + 1.96 \frac{1.7}{\sqrt{85} })<em></em>

<em>( 6.5 - 0.3614 , 6.5 + 0.3614 )</em>

<em>( 6.1386 , 6.8614)</em>

<u><em>Conclusion</em></u><em>:-</em>

<em>95% of confidence interval for the Population</em>

<em>( 6.1386 , 6.8614)</em>

8 0
4 years ago
The temperature, T, of a given mass of gas varies inversely with its Volume,V. The temperature of 98 cm ³ of a certain gas is 28
Naily [24]

Answer:

T₂ = 421.4 K

Step-by-step explanation:

The temperature, T, of a given mass of gas varies inversely with its Volume,V.

T\propto \dfrac{1}{V}\\\\V_1T_1=V_2T_2

We have,

V₁ = 98 cm³, T₁ = 28° C = (28+273) K = 301 K

V₂ = 70 cm₃

We need to find the new temperature of the gas. Using the above relation to find T₂.

T_2=\dfrac{V_1T_1}{V_2}\\\\T_2=\dfrac{98\times 301}{70}\\\\T_2=421.4\ K

Hence, the required temperature of the gas is 421.4 K.

4 0
3 years ago
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