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SpyIntel [72]
3 years ago
12

Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.

Mathematics
1 answer:
astra-53 [7]3 years ago
7 0

Answer:

\frac{dy}{dx}=\frac{1}{2(x-4)}

Step-by-step explanation:

We are given that a function  

y=ln(x-4)^{\frac{1}{2}}

We have to find the derivative of the function

y=\frac{1}{2}ln(x-4)

By using lna^b=blna

Differentiate w.r.t x

\frac{dy}{dx}=\frac{1}{2}\times \frac{1}{x-4}

By using formula

\frac{d(lnx)}{dx}=\frac{1}{x}

\frac{dy}{dx}=\frac{1}{2(x-4)}

Hence, the derivative of function

\frac{dy}{dx}=\frac{1}{2(x-4)}

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If the diameter of the circle below is 16 in., what is the area of the circle?
mote1985 [20]

Answer:

64π inches² (approximately 201.06 inches²)

Step-by-step explanation:

A=\pi r^2 where r is the radius

To find the radius, divide the diameter by 2

16 ÷ 2 = 8 inches

Plug in 8 as the radius

A=\pi (8)^2\\A=64\pi

A=201.06 (approximately)

Therefore, the area of the circle is 64π inches², or approximately 201.06 inches².

I hope this helps!

8 0
3 years ago
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How do I solve this problem? Thank you.
algol13
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What is the area of the kite? Height of 6ft base of 14ft. 21 square feet 40 square feet 42 square feet 84 square feet
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Let V be a vector space of dimension 4. Determine if each statement is true or false. (a) Any set of 5 vectors in V must be line
son4ous [18]

Answer:

a) True

b) False

c) False

d) False

e) True

Step-by-step explanation:

a) Each basis of V has four vectors. Then any set of 5 vectors must be linear dependent (LD).

b) Suppose that \{v_1,v_2,v_3,v_4\} is a basis of V. Considere the set A=\{v_1,\lambda_1v_1,\lambda_2v_1,v_2,v_3\} where \lambda_1, \lambda_2 are scalars. The set has 5 vectors but V\neq span(A) because v_4 is not belong to A and v_4  is linear independent of v_1

c)  Suppose that \{v_1,v_2,v_3,v_4\} is a basis of V. Considere the set A=\{v_1,\lambda_1v_1,\lambda_2v_1,\lambda_3v_1\} where \lambda_1, \lambda_2,\lambda_3 are scalars. A has four nonzero vectors but isn't a basis because is a LD set.

d)  Suppose that \{v_1,v_2,v_3,v_4\} is a basis of V. Considere the set A=\{v_1,\lambda_1v_1,\lambda_2v_1\} where \lambda_1, \lambda_2 are scalars. A has 3 nonzero vectors but isn't a basis because is a LD set.

e)  Since any basis of V must have 4 elements, then a set of three vectors cannot generate V.

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2 years ago
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