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anastassius [24]
3 years ago
5

Be sure to answer all parts. Identify the structures of isomers A and B (molecular formula C9H10O). Compound A: IR peak at 1742

cm−1; 1H NMR data (ppm) at 2.15 (singlet, 3 H), 3.70 (singlet, 2 H), and 7.2−7.4 (multiplet, 5 H). Compound B: IR peak at 1688 cm−1; 1H NMR data (ppm) at 1.22 (triplet, 3 H), 2.98 (quartet, 2 H), and 7.28−7.95 (multiplet, 5 H). Compound A: draw structure ... Compound B: draw structure ...

Chemistry
1 answer:
Ivanshal [37]3 years ago
4 0

Answer:

Explanation:

check the attachment for the structure diagrams

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The two weather maps show a front moving across Texas in which of the following cities would a decrease in temperature be predic
Nadusha1986 [10]

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San Antonio and Dallas Texas

Explanation:

8 0
4 years ago
Chemistry help. I need help with an assignment due in 20 minutes.
jasenka [17]

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wheres the pic of it?

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3 years ago
Two metals (Metal A and Metal B) are both exposed to a laser which emits photons that have a greater energy than the work functi
Tresset [83]

Answer:

shorter than

equal to

Explanation:

Let us go back to the Einstein photoelectric equation;

KE = E - Wo

Where

KE = kinetic energy of the photoelectron

E = energy of the incident photon

Wo = work function of the metal

But KE = 1/2mv^2

Thus the velocity of the emitted photoelectron  is determined by the kinetic energy of the emitted photoelectron.

Since the work function of metal A is smaller than that of metal B, the kinetic energy of photoelectrons emitted from metal A is greater than that of photoelectrons emitted from metal B . Therefore, the velocity of electrons from metal A is greater than those from metal B.

From de Broglie relation;

λ = h/mv

Where;

λ = de Broglie wavelength

h = Plank's constant

m = mass

v = velocity

Metal A producing electrons with greater velocity will lead to a shorter de Broglie wavelength compared to those from metal B.

The number of photoelectrons ejected is determined by the intensity of the photons and not the energy of the incident photons or the work function of the metals. Since the two metals are exposed to the the same laser, equal number of photoelectrons are produced for metals A and B.

8 0
3 years ago
ClO(4)− Express your answer as a chemical formula.
Nimfa-mama [501]

ClO(4)− is regarded as perchlorate ion and are produced commercially in most situations as salts via industries and in the laboratory.

<h3>What is Perchlorate ion?</h3>

This ion is referred to as a monovalent inorganic anion and is obtained by deprotonation of perchloric acid. It is composed of chlorine and oxygen atoms in the ratio 1 to 4 respectively.

This has  32 valence electrons available in the Lewis structure and is used in the commercial production of solid rocket fuel.This ion has a molar mass of 99.451 g mol−1 and is used in different processes such as an oxidizer and to control static electricity during the process of food preservation in industries.

Therefore ClO₄− is also regarded as perchlorate ion and is the most appropriate choice.

Read more about Perchlorate ion here brainly.com/question/16895150

#SPJ1

3 0
2 years ago
An unknown metal sample has a mass : of 11.29. and a volume of 2 cm3. What is the : density of the unknown metal? ​
tatuchka [14]

Answer:

\boxed{\sf Density \ of \ the \ unknown \ metal = 5.645 \ g/cm^3}

Given:

Mass = 11.29 g

Volume = 2 cm³

To Find:

Density of unknown metal

Explanation:

Formula:

\boxed{ \bold{Density = \frac{Mass}{Volume}}}

Substituting value of mass & volume in the formula:

\sf \implies Density =  \frac{11.29}{2} \\  \\   \sf \implies Density =  5.645 \: g/cm^3

3 0
3 years ago
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