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Tresset [83]
3 years ago
13

. In what way is kinetic energy present in a solar oven

Chemistry
1 answer:
Afina-wow [57]3 years ago
6 0
Answer:

Energy of motion is called
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A sample of a gas has a volume of 852 mL at 298 K. If the gas is cooled to 200K, what would the new volume be?
Colt1911 [192]

Answer:

571.81 mL

Explanation:

Assuming constant pressure, we can solve this problem by using <em>Charles' law</em>, which states that at constant pressure:

  • V₁T₂=V₂T₁

Where in this case:

  • V₁ = 852 mL
  • T₂ = 200 K
  • V₂ = ?
  • T₁ = 298 K

We <u>input the data</u>:

  • 852 mL * 200 K = V₂ * 298 K

And <u>solve for V₂</u>:

  • V₂ = 571.81 mL

The new volume would be 571.81 mL.

4 0
3 years ago
You are pushing on a heavy door, trying to slide it open. If your friend stands behind you and helps you push, how have the forc
NeTakaya

Answer:

o tudo bie ms ouemuyllen quearomuit oajuda rvoc  mi psarcisoqu e termnei ed cmoepetar esta questlã.oê

Explanation:

a egur oguta nestáincompel ta

6 0
2 years ago
The continental crust is _________ than the oceanic crust and seems to "float" on the mantle.
zavuch27 [327]
The continental crust is less dense than the <span>oceanic crust and seems to "float" on the mantle.</span>
4 0
2 years ago
If there are only a few remaining members of an insect species living in one area, which would most likely cause this species to
Zepler [3.9K]

Answer:

New predators and not a lot of food

Explanation:

If new predators come than they can eat the insects and go extinct. Also if there is not a lot if food than the will die because they have nothing to eat.

7 0
2 years ago
A sample of CaCO3(s) is introduced into a sealed container of volume 0.638 L and heated to 1000 K until equilibrium is reached.
JulsSmile [24]

Answer:

the mass of CaO present at equilibrium is, 0.01652g

Explanation:

K_p = [CO_2] = 3.8×10⁻²

Now we have to calculate the moles of CO₂

Using ideal gas equation,

PV =nRT

P = pressure of gas = 3.8×10⁻²

T = temperature of gas = 1000 K

V = volume of gas = 0.638 L

n = number of moles of gas = ?

R = gas constant = 0.0821 L.atm/mole.k

\frac{3.8 * 10^2 * 0.638}{0.0821 * 1000} \\= 2.95 * 10^-^4

Now we have to calculate the mass of CaO

mass = 2.95 * 10 ⁻⁴ × 56

= 0.01652g

Therefore,

the mass of CaO present at equilibrium is, 0.01652g

7 0
3 years ago
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