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3 years ago

How do you solve questions 6 and 7

Chemistry

1 answer:

bearhunter [10]3 years ago

6 0

I know the answer to your question but if you want me to answer this question first, I need your help with my question "How do I solve number 12? Quick please I need help ASAP!!!"

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Which cells produce photosynthesis

AnnZ [28]

Hey there,

Answer:

Photosynthetic cell

Hope this helps :D

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3 years ago

Atomic number of f^-1

victus00 [196]

The atomic number is 9 Ions have the same atomic number since atomic number signifies number of protons not electrons

7 0

3 years ago

At 25°C, the equilibrium constant Kc for the reaction in thesolvent CCl4 2BrCl <----> Br2 + Cl2 is 0.141. If the initial c

ivolga24 [154]

Answer: The equilibrium concentration of bromine gas is 0.00135 M

Explanation:

We are given:

Initial concentration of chlorine gas = 0.0300 M

Initial concentration of bromine monochlorine = 0.0200 M

For the given chemical equation:

$2BrCl\rightleftharpoons Br_2+Cl_2$

Initial: 0.02 0.03

At eqllm: 0.02-2x x 0.03+x

The expression of $K_c$ for above equation follows:

$K_c=\frac{[Br_2]\times [Cl_2]}{[BrCl]^2}$

We are given:

$K_c=0.141$

Putting values in above equation, we get:

$0.141=\frac{x\times (0.03+x)}{(0.02-2x)^2}\\\\x=-0.96,+0.00135$

Neglecting the value of x = -0.96 because, concentration cannot be negative

So, equilibrium concentration of bromine gas = x = 0.00135 M

Hence, the equilibrium concentration of bromine gas is 0.00135 M

8 0

3 years ago

An atom in the ground state contains 8 valence electrons this atom is classified as a

Alekssandra [29.7K]

Noble Gas. Metals have 1 or 2 Valence Electrons. Halogens have 7 Valence Electrons. Semi-Metals can have different amounts.

5 0

3 years ago

Read 2 more answers

What is the [H+] concentration of blood, given the ph is 2.5?

belka [17]

Answer:

0.00316

Explanation:

You have to use the following equation:

$pH=-log[H^+]$

You are given the pH and need to find the concentration of H+. Plug in the given components and solve.

$2.5=-log[H^+]\\H^+ = 10^{-2.5}\\H^+=0.00316$

The concentration of H is 0.00316.

8 0

3 years ago