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3 years ago

Solve for c in this questiona(c-b)=d

Mathematics

1 answer:

Soloha48 [4]3 years ago

8 0

a(c - b) = d

Divide "a" on both sides

c - b = $\frac{d}{a}$

Add "b" on both sides to get "c" by itself

c = $\frac{d}{a} + b$

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Find the inverse of f(x)=x/4-7

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A plane flying horizontally at an altitude of "1" mi and a speed of "430" mi/h passes directly over a radar station. Find the ra

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Answer:

The rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.

Step-by-step explanation:

Given information:

A plane flying horizontally at an altitude of "1" mi and a speed of "430" mi/h passes directly over a radar station.

$z=1$

$\frac{dx}{dt}=430$

We need to find the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station.

$y=2$

According to Pythagoras

$hypotenuse^2=base^2+perpendicular^2$

$y^2=x^2+1^2$

$y^2=x^2+1$ .... (1)

Put z=1 and y=2, to find the value of x.

$2^2=x^2+1^2$

$4=x^2+1$

$4-1=x^2$

$3=x^2$

Taking square root both sides.

$\sqrt{3}=x$

Differentiate equation (1) with respect to t.

$2y\frac{dy}{dt}=2x\frac{dx}{dt}+0$

Divide both sides by 2.

$y\frac{dy}{dt}=x\frac{dx}{dt}$

Put $x=\sqrt{3}$ , y=2, $\frac{dx}{dt}=430$ in the above equation.

$2\frac{dy}{dt}=\sqrt{3}(430)$

Divide both sides by 2.

$\frac{dy}{dt}=\frac{\sqrt{3}(430)}{2}$

$\frac{dy}{dt}=372.390923627$

$\frac{dy}{dt}\approx 372$

Therefore the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.

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4 years ago

We discovered that 650 GSS respondents in 2006 watched television for an average of 2.98 hrs/day, with a standard deviation of 2

Aliun [14]

Answer:

a) 2.09167

b) 0.2

c) 130 correspondents

d) 5.38 hours per day

e) 69%

Step-by-step explanation:

The formula for calculating a z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

Mean = 2.98hrs/day, Standard Deviation = 2.4

a) What is the Z score for a person who watches more than 8 hrs/day.

z = 8 - 2.98/2.4

= 2.09167

b) What proportion of people watch 5 hrs/day or more television?

z = 5 - 2.98/2.4

z = 0.84167

Determining the Probabilityvalue from Z-Table:

P(x<5) = 0.80001

The proportion of people watch 5 hrs/day or more television

P(x>5) = 1 - P(x<5) = 0.19999

Approximately = 0.2

c) How many does this correspond to in the sample?

From the question above, we are told that: there are 650 GSS respondents in 2006 watched television

Hence the proportion that corresponds to Question b is

0.2 × 650

= 130 correspondents

Therefore, 130 correspondents watch 5 hrs a day or more television

d) What number of television hours per day corresponds to a Z = +1.

z score formula is given as:

z = (x-μ)/σ

Z = +1

x = unknown

Mean = 2.98

Standard deviation = 2.4

Hence:

1 = x - 2.98/2.4

Cross Multiply

1 × 2.4 = x - 2.98

2.4 = x - 2.98

2.4 + 2.98 + x

= 5.38 hours per day.

e)What is the percentage of people who watch between 1 and 6 hours of television per day?

For x = 1

z = 1 - 2.98/2.4

z = -0.825

Probability value from Z-Table:

P(x= 1) = 0.20469

For x = 6

z = 6 - 2.98/2.4

z = 1.25833

Probability value from Z-Table:

P(x = 6) = 0.89586

The percentage of people who watch between 1 and 6 hours of television per day is calculated as:

P(x = 6) - P(x = 1)

0.89586 - 0.20469

= 0.69117

Converting to percentage,

0.69117 × 100%

= 69.117%

To the nearest whole number = 69%

Therefore, 69% of the people who watch between 1 and 6 hours of television per day

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4 years ago

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stich3 [128]

$y-2=-\frac{1}{3}(x+6)\\y=-\frac{1}{3}(x+6)+2$

Simply move -2 to another side.

$y=-\frac{x}{3}-2+2$

Distribute -1/3 in (x+6)

$y=-\frac{x}{3}$ ---> Answer

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3 years ago

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