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Lynna [10]
3 years ago
11

what could backupdocs.com documents backup pdf program handle at one point if at all backupdocs.com functions documents saving p

rograms
Computers and Technology
1 answer:
bekas [8.4K]3 years ago
6 0
This don’t make sense?? But I think it can handle it aha
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Two functions of the UPS​
Angelina_Jolie [31]

Answer:

UPS is abbreviation of Uninterrupted power supply. It is a battery backup devices useful when major supply is interrupted due to any reason.

It performs the following functions:

1. It provides protection from power surges.

2. Smooth out noisy power sources

5 0
4 years ago
Read 2 more answers
04. Suppose a computer program needs to sort a list of student records in ascending order
34kurt

Answer:

D) ["Kathy Bones", "Jill Brewer", "Joe Schnook", "Tom Smith"]

Explanation:

The context of the problem explains a computer program that sorts names in "ascending order" (A to Z) since the ASCII table has capital A start a lower number and it increases from there to capital Z.

Notice how the attached file, which is a portion of the ASCII table, shows that letters after A are also higher in decimal value than the previous letter.

With this in mind, we know that all this program does is sort by last name alphabetical order. From there, just sort the given names using that same criteria, last name alphabetical order, and the correct answer is determined.

<em>Please put "Brainliest" on my answer if it helped you out!</em>

<em>If you want to learn more about this subject, you can search:</em>

<em>- ASCII Table</em>

<em>- Lists in Programming</em>

<em>- Sorting Procedures</em>

7 0
2 years ago
Where is the best place to self learn c++ or c# that is free?
Elina [12.6K]

Answer:

udemy

Explanation:

Hello guys, you might know that C++ is one of the most popular and powerful object-oriented programming languages and if you want to do low-level stuff then it’s the best language to start with.

You will find applications written in C++ on a wide range of fields like embedded programming, server-side application, gaming, and even high-frequency trading applications. Most of the complex software like Operating Systems, Database Management Systems, and Powerful trading systems are written in C++.

While many of us have learned to program by using C and C++, let me honest with you learning C++ is challenging. There are many areas that are tough to grasp like points but you will learn them slowly and that’s where these free C++ courses will help you.

There is no doubt that learning C++ will open several opportunities for you. There is a huge demand for good C++ developers, especially in the area of high-frequency trading where every microsecond matter and power of C++ is absolutely needed.

C++ is the language which provides the best of both world, it allows you to use OOP to manage the complexity of software but at the same time, it also allows you to get close to your machine and access all of your computer’s hardware, which is not easily possible for other object-oriented languages like Java or Python.

That’s the reason C++ is heavily used for writing native device drivers, high-end desktop games and complex artificial intelligence programs where you need high performance.

In this article, I am going to share with you some of the best and free courses to learn C++ online at your own time and place and free of cost. You can use these courses if you are starting with programming or you have some experience in coding but not familiar with C++.

4 0
3 years ago
Read 2 more answers
Write a procedure named Str_find that searches for the first matching occurrence of a source string inside a target string and r
kirill115 [55]

Answer: Provided in the explanation section

Explanation:

Str_find PROTO, pTarget:PTR BYTE, pSource:PTR BYTE

.data

target BYTE "01ABAAAAAABABCC45ABC9012",0

source BYTE "AAABA",0

str1 BYTE "Source string found at position ",0

str2 BYTE " in Target string (counting from zero).",0Ah,0Ah,0Dh,0

str3 BYTE "Unable to find Source string in Target string.",0Ah,0Ah,0Dh,0

stop DWORD ?

lenTarget DWORD ?

lenSource DWORD ?

position DWORD ?

.code

main PROC

  INVOKE Str_find,ADDR target, ADDR source

  mov position,eax

  jz wasfound           ; ZF=1 indicates string found

  mov edx,OFFSET str3   ; string not found

  call WriteString

  jmp   quit

wasfound:                   ; display message

  mov edx,OFFSET str1

  call WriteString

  mov eax,position       ; write position value

  call WriteDec

  mov edx,OFFSET str2

  call WriteString

quit:

  exit

main ENDP

;--------------------------------------------------------

Str_find PROC, pTarget:PTR BYTE, ;PTR to Target string

pSource:PTR BYTE ;PTR to Source string

;

; Searches for the first matching occurrence of a source

; string inside a target string.

; Receives: pointer to the source string and a pointer

;    to the target string.

; Returns: If a match is found, ZF=1 and EAX points to

; the offset of the match in the target string.

; IF ZF=0, no match was found.

;--------------------------------------------------------

  INVOKE Str_length,pTarget   ; get length of target

  mov lenTarget,eax

  INVOKE Str_length,pSource   ; get length of source

  mov lenSource,eax

  mov edi,OFFSET target       ; point to target

  mov esi,OFFSET source       ; point to source

; Compute place in target to stop search

  mov eax,edi    ; stop = (offset target)

  add eax,lenTarget    ; + (length of target)

  sub eax,lenSource    ; - (length of source)

  inc eax    ; + 1

  mov stop,eax           ; save the stopping position

; Compare source string to current target

  cld

  mov ecx,lenSource    ; length of source string

L1:

  pushad

  repe cmpsb           ; compare all bytes

  popad

  je found           ; if found, exit now

  inc edi               ; move to next target position

  cmp edi,stop           ; has EDI reached stop position?

  jae notfound           ; yes: exit

  jmp L1               ; not: continue loop

notfound:                   ; string not found

  or eax,1           ; ZF=0 indicates failure

  jmp done

found:                   ; string found

  mov eax,edi           ; compute position in target of find

  sub eax,pTarget

  cmp eax,eax    ; ZF=1 indicates success

done:

  ret

Str_find ENDP

END main

cheers i hoped this helped !!

6 0
3 years ago
If a computer reboots itself on its own the computer might have a(n)
MissTica

Answer:

D. Software Problem

Explanation:

It could be that the software is bootlooping which will power on and off until its fixed.

4 0
3 years ago
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