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kirill115 [55]
3 years ago
14

Solve 4^(2x) = 7^(x−1).

Mathematics
1 answer:
sweet [91]3 years ago
3 0
To solve for x in the given equation, use natural logarithms. Getting the natural logarithms of both sides, will be ln 4^(2x) = ln 7^(x-1). This is also equal to 2x ln 4 = (x-1) ln 7. Rearranging the equation, 2x/(x-1) = ln 7/ln 4. The right side is equal to 1.4037. Thus, the value of x is -2.3539. 
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Which of the following series are convergent?
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Answer:

All of them

Step-by-step explanation:

According to the ratio test, for a series ∑aₙ:

If lim(n→∞) |aₙ₊₁ / aₙ| < 1, then ∑aₙ converges.

If lim(n→∞) |aₙ₊₁ / aₙ| > 1, then ∑aₙ diverges.

(I) aₙ = 10 / n!

lim(n→∞) |(10 / (n+1)!) / (10 / n!)|

lim(n→∞) |(10 / (n+1)!) × (n! / 10)|

lim(n→∞) |n! / (n+1)!|

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0 < 1

This series converges.

(II) aₙ = n / 2ⁿ

lim(n→∞) |((n+1) / 2ⁿ⁺¹) / (n / 2ⁿ)|

lim(n→∞) |((n+1) / 2ⁿ⁺¹) × (2ⁿ / n)|

lim(n→∞) |(n+1) / (2n)|

1/2 < 1

This series converges.

(III) aₙ = 1 / (2n)!

lim(n→∞) |(1 / (2(n+1))!) / (1 / (2n)!)|

lim(n→∞) |(1 / (2n+2)!) × (2n)! / 1|

lim(n→∞) |(2n)! / (2n+2)!|

lim(n→∞) |1 / ((2n+2)(2n+1))|

0 < 1

This series converges.

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235

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