Question

Solve 4^(2x) = 7^(x−1).

Answer 1

To solve for x in the given equation, use natural logarithms. Getting the natural logarithms of both sides, will be ln 4^(2x) = ln 7^(x-1). This is also equal to 2x ln 4 = (x-1) ln 7. Rearranging the equation, 2x/(x-1) = ln 7/ln 4. The right side is equal to 1.4037. Thus, the value of x is -2.3539.