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ruslelena [56]
3 years ago
7

What is the equation of the graph below?

Mathematics
1 answer:
oee [108]3 years ago
8 0

Answer:

B) y=-(x-3)^{2}+2

Step-by-step explanation:

We are given,

The graph of the parabola opens downwards.

This means that the leading co-efficient of the function will be negative.

So, options C and D are not possible.

Moreover, it is given that the graph cuts x-axis near 1\frac{1}{2} i.e. \frac{3}{2} = 1.5 and 4\frac{1}{2} i.e. \frac{9}{2} = 4.5.

i.e. At y=0, the value of x is near \frac{3}{2} and \frac{9}{2}.

A. So, in y=-(x+2)^{2}+2, we put y =0.

i.e. (x+2)^{2}=2

i.e. x=-2\pm \sqrt{2}

i.e. x = 0.68 and x = 3.41

We see that this does not crosses the x-axis at the given points.

So, option A is wrong.

B. Also, in y=-(x-3)^{2}+2, we put y =0.

i.e. (x-3)^{2}=2

i.e. x=3\pm \sqrt{2}

i.e. x = 1.68 and x = 4.41.

Thus, this equation cuts the x-axis near the given points i.e. 1.5 and 4.5.

Hence, the equation of the given graph is y=-(x-3)^{2}+2.

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