3 years ago

What value of x makes the equation true? 3(x − 4) = 15 a -1 b 1 c 7 d 9

Mathematics

1 answer:

denis23 [38]3 years ago

7 0

The answer is : D. 9

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$\frac{x^2}{12}-\frac{y^2}{4}=1$

Step-by-step explanation:

Since our foci are located on the x-axis, then our major axis is going to be the horizontal transverse axis of the hyperbola:

<u>Formula for hyperbola with horizontal transverse axis centered at origin</u>

<u /> $\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$
Directrices -> $x=\pm\frac{a^2}{c}$
Foci -> $(\pm c,0)$ where $a^2+b^2=c^2$
$a>b$

Since we are given our directrices of $x=\pm3$ and foci of $(\pm4,0)$ , then we can set up the directrices equation to solve for $a^2$ :

$x=\pm\frac{a^2}{c}\\ \\\pm3=\pm\frac{a^2}{4}\\ \\12=a^2$

Now we can determine $b^2$ to complete our equation for the hyperbola:

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Therefore, our equation for our hyperbola is $\frac{x^2}{12}-\frac{y^2}{4}=1$

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