Answer:
Step-by-step explanation:
To get the reasonable range of the situation, we will find the minimum value and maximum value of the calories that can be dressed.
The minimum occur at when x = 0
f(0) = 100(0) +50.
f(0) = 50
Hence the minimum value of the calorie is 50.
The maximum value occur at f'(x)
f'(x) = 100
Hence the maximum value of the calorie is 100
Hence, the reasonable range for the situation is 50 ≤ x ≤ 100
Answer:
<u>Properties of a rhombus used to solve the following </u>
- <em>Opposite angles are congruent</em>
- <em>Diagonals are angle bisectors</em>
- <em>Diagonals are perpendicular to each other</em>
- <em>Adjacent angles are supplementary</em>
(30)
- ∠2 = ∠3 = ∠5 = 27°
- ∠1 = ∠4 = 180° - (2*27°) = 126°
(31)
- ∠4 = 70°
- ∠1 = ∠2 = ∠3 = ∠5 = 1/2(180° - 70°) = 1/2(110°) = 55°
(32)
- ∠1 = ∠2 = ∠5 = 90° - 26° = 64°
- ∠3 = 26°
- ∠4 = 90°
Answer:
see below
Step-by-step explanation:
A = pi r^2
If they have the same radius they have the same area
A two circles = pi r^2 +pi r^2
= 2 pi r^2
If we double the radius
A = pi (2r)^2
= pi 4r^2
The combined area of two circles is 1/2 the area as the area of a circle with twice the radius.
