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iris [78.8K]
3 years ago
14

The diagram shows one step in the process of protein synthesis. mc015-1.jpg What is the purpose of the peptide bond that is show

n in the diagram? It connects amino acids. It connects ribosomes. It connects tRNA. It connects anticodons.
Biology
2 answers:
leonid [27]3 years ago
9 0
Connects amino acids
Alenkinab [10]3 years ago
7 0

The right answer is It connects amino acids.

• Amino acids are the building blocks of proteins.

• There are 21 amino acids, but only one type of binding used to connect them: it is the peptide bond.

The peptide bond is formed during the translation step by a covalent bond between an α-amino group of an amino acid and the carboxylic group of another amino acid. A molecule of water is eliminated.

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Brown eyes are dominant to blue eyes. Which the genotype Bb what color will the child’s eyes be?
SIZIF [17.4K]

Answer:

Brown eyes will be dominant so that'll be the child's eye color

Explanation:

4 0
2 years ago
Compare and contrast an exothermic chemical reaction and an exothermic solution formation by dissociation
saw5 [17]
An exothermic chemical reaction is  change in the chemicals that can never be undone, an exothermic solution is a combination of chemicals 
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3 years ago
How is carbon brought into the ocean
stiv31 [10]

Answer and Explanation:

The ocean takes up carbon dioxide through photosynthesis by plant-like organisms (phytoplankton), as well as by simple chemistry: carbon dioxide dissolves in water. It reacts with seawater, creating carbonic acid. ... In the center of the ocean, wind-driven currents bring cool waters and fresh carbonate to the surface.

Hope this help if it did plz mark brainliest

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4 0
3 years ago
Read 2 more answers
In Drosophila, the genes for withered wings (whd), smooth abdomen (sm) and speck body (sp) are located on chromosome 2 and are s
lesya692 [45]

Answer:

A) 47; B) 33; C) 272; D) 122

Explanation:

The three genes are linked.

The female with withered wings and a smooth abdomen has the genotype whd sm sp+/whd sm sp+.

The male with a speck body has the genotype whd+ sm+ sp/whd+ sm+ sp.

Both individuals are homozygous for all genes, so each of them only produces one type of gamete. The resulting F1 therefore has the genotype whd sm sp+/ whd+ sm+ sp, heterozygous for all genes and with a wild-type phenotype.

The females of the F1 were mated with homozygous recessive males (test cross): whd sm sp/whd sm sp.

<h3>A)</h3>

If we assume interference is 0, the probability of crossing over happening between the genes whd and sm is independent from the probability of crossing over happening between sm and sp.

The distance = frequency of recombination × 100, so the frequency of recombination (RF) between genes whd and sm is 0.305 and the RF between genes sm and sp is 0.155.

<u>The expected double crossover progeny among the 1000 offspring will be:</u>

RF whd-sm × RF sm-sp  × 1000 =

0.305  × 0.155 × 1000 = 47 individuals will be double crossover.

<h3>B)</h3>

Interference is 0.3

The interference is calculated as 1- coefficient of coincidence (cc).

cc = observed double crossover/expected double crossover

Therefore:

I = 1 - cc

cc = 1 - I

<u>cc = 0.7</u>

Observed DCO / 47 = 0.7

Observed DCO = 0.7  × 47

Observed DCO ≅ 33

<h3>C)</h3>

The parental gametes are whd sm sp+ and whd+ sm+ sp (the genotype of the F1 female is known).

Looking at them and at the gene map we can tell that the gametes that give rise to withered wings, speck body (whd sm+ sp) and smooth abdomen (whd+ sm sp+) phenotypes are the result of recombination occurring between genes whd and sm.

To calculate the expected number of individuals with those phenotypes among the 1000 progeny we need to determine the frequency of recombination between the genes whd and sm considering there's interference.

The distance whd-sm = RF x 100

The recombination frequency is the sum of the single crossover between whd and sm and the double crossovers.

The frequency of DCO is 33/1000=0.033.

Distance whd-sm/ 100 = SCOwhd-sm + DCO

0.305 - 0.033 = SCO whd-sm

<u>Frequency of SCO whd-sm= 0.272</u>

And the expected number of individuals with those phenotypes will be 0.272 x 1000 = 272.

<h3>D)</h3>

The gametes that originate the phenotypes withered wings, speck body, smooth abdomen (whd sm sp) and wild type (whd+ sm+ sp+) are the result of recombination between genes sm and sp.

Distance sm-sp/ 100 = SCOsm-sp + DCO

0.155 - 0.033 = SCOsm-sp

<u>Frequency of SCO sm-sp= 0.122</u>

And the expected number of individuals with those phenotypes will be 0.122 x 1000 = 122.

6 0
3 years ago
In pea plants, red flowers and round pollen are known to be recessive traits. In a dihybrid cross experiment, lots of plants wit
motikmotik

Answer:

The last one if there are multiple answers please tell me.

Explanation:

just when with the one i knew in heart

8 0
3 years ago
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