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3 years ago

15

Please help! First-person to answer gets Brainliest!!!

1 answer:

Harlamova29_29 [7]3 years ago

6 0

i'm sorry but i don't know i wish you alot of luck on what you are working on

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What’s 5x[(26-4)-(4+6)

seropon [69]

Answer:

The Answer is: The factors reduce to 60x.

Step-by-step explanation:

First the parenthesis, then the bracket, then the multiplication:

5x[(26 - 4) - (4 + 6)]

5x[22 - 10]

5x[12]

60x

Hope this helps! Have an Awesome Day!! :-)

8 0

3 years ago

Read 2 more answers

HELP WITH ANY OR ALL THESE PROBLEMS ASAP PLEASE LIKE NOW PLEASE<br>CAN SOMEONE PLEASE HELP

LiRa [457]

Ques 8:

The Volume(V) in cubic feet of an aquarium id modeled by the polynomial function V(x)= $x^{3}+2x^{2}-13x+10$

a) We have to explain that why x =4 is not a possible rational zero.

By Factor theorem, which states that a polynomial f(x) has a factor (x - k) if and only if f(k)=0.

For this , we will substitute the value of x in the given function.

$V(x)=x^{3}+2x^{2}-13x+10$

$V(4)=4^{3}+2(4)^{2}-13(4)+10$

$V(4)=4^{3}+2(4)^{2}-13(4)+10$

$V(4)=54$ which is not equal to zero.

Therefore, x=4 is not a possible rational zero.

(b) To show that (x-1) is a factor of V(x).

By Factor theorem, which states that a polynomial f(x) has a factor (x - k) if and only if f(k)=0.

Let (x-1)=0

So, x=1.

Substituting x=1 in the given function.

$V(1)=1^{3}+2(1)^{2}-13(1)+10$

$V(1)= -10+10$

V(1) = 0

Therefore, (x-1) is a factor of V(x).

Now we will factorize the given function.

Dividing the given function by (x-1).

On dividing, we get quotient as $x^{2}+3x-10$

So, factored form is = $(x-1)(x^{2}+3x-10)$

= $(x-1)(x^{2}+5x-2x-10)$

= $(x-1)(x(x+5)-2(x+5))$

= $(x-1)(x+5)(x-2)$

(c) So, the dimensions are 1,2 and -5.

5 0

3 years ago

Jose needs to enclose a rectangular section of his yard. The perimeter of the section is 27 feet, and the area is 35 square foot

Ratling [72]

A = 35 sq ft
<span>L = 10 ft </span>
<span>W = 3.5 ft</span>

3 0

3 years ago

Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

3 years ago

Given the function g(x) = 8x − 2, compare and contrast g(−2) and g(4). Choose the statement that is true concerning these two va

Anit [1.1K]

G(-2) = 8(-2) -2 = -16 - 2 = -18
g(4) = 8*(4) - 2 = 32 - 2 = 30
as you can see 30 is greater than -18 so the answer is C

6 0

3 years ago

Read 2 more answers