Question

segment AB is dilated from the origin to create segment A prime B prime at A' (0, 6) and B' (6, 9). What scale factor was segment AB dilated by?

Answer 1

Answer:

Scale factor is 3.

Step-by-step explanation:

Given: The Line Segment AB is dilated and a line segment A'B' is created.

A' (0, 6) and B' (6, 9).

As per the given graph , we can easily see that the coordinates of A and B are

A(0, 2) and B(2, 3)

Please refer to attached graph for the coordinates of A', B' and A, B.

The distance formula is given as:

$D =\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

D is the distance between two coordinates $(x_1,y_1)$ and $(x_2,y_2)$.

So, the distance AB = $\sqrt{(2-0)^2+(3-2)^2} = \sqrt{5}$

Similary, distance A'B' = $\sqrt{(6-0)^2+(9-6)^2} = \sqrt{36 + 9}=\sqrt{45} = 3\sqrt{5}$

We can clearly see that A'B' is three times the distance AB.

So, The scale factor 3.

Answer 2

Answer:

the scale factor is definently 3

Step-by-step explanation: