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monitta
3 years ago
9

HELPPP!!

Mathematics
2 answers:
Alex73 [517]3 years ago
8 0

Answer:

Step-by-step explanation:

they are congruent. sides CB and ZY are congruent. sides AB and XY are congruent. the angle at points C and Z are congruent.

Ksivusya [100]3 years ago
7 0

Answer : Yes, there is enough information to prove the following triangles are congruent.

Step-by-step explanation :

The following combinations of the congruent triangle facts  will be sufficient to prove triangles congruent.

The combinations are:

(1) SSS (side-side-side) : If three sides of a triangle are congruent to three sides of another triangle then the triangles are congruent.

(2) SAS (side-angle-side) : If two sides and included angle of a triangle are congruent to another triangle then the triangles are congruent.

(3) ASA (angle-side-angle) : If two angles and included side of a triangle are congruent to another triangle then the triangles are congruent.

(4) RHS (right angle-hypotenuse-side) : If the hypotenuse and leg of one right triangle are congruent to the corresponding parts of another right triangle, the right triangles are congruent.

As we are given two triangles.

Prove : ΔABC ≅ ΔXYZ

As,

Side AB = Side XY    (side)

Side BC = Side YZ     (side)

∠C = ∠Z                     (angle)

That means, in this two sides and included angle of a triangle are equal to another triangle then the triangles are congruent.

So, ΔABC ≅ ΔXYZ

Hence, yes, there is enough information to prove the following triangles are congruent.

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A woman bought a new color television with
attashe74 [19]

Answer:

B

Step-by-step explanation:

6 0
3 years ago
Is it possible to solve a quadratic equation that is not factorable over the set of integers? Explain.
zvonat [6]

Answer:

Yes

Step-by-step explanation:

Yes it is possible to solve a quadratic equation that is not factorable over the set of integers.

The solution may vary like Integers, rationals, irrationals or complex solutions.

To find two roots of the equation we can always use the formula given below to solve a quadratic equation,

For the quadratic equation,

ax^2+bx+c=0, we have,

x= \frac{-b\pm \sqrt{b^2-4 ac}}{2a}

If the discriminant is greater than b^2, we get complex roots.

8 0
3 years ago
A certain bag of potting soil is 1/4 peat moss, and the rest is dirt. What part is dirt?
Troyanec [42]

Answer:

D = 1 - \frac{1}{4}

D = \frac{3}{4}

Step-by-step explanation:

Given:

1 bag of potting soil

Peat Moss = \frac{1}{4}

Required

What part is dirt?

The whole bag of potting soil is represented as 1;

Let P represent Peat Moss and D represented Dirt; Such that

P + D = 1

Subtract P from both sides

P - P + D = 1 - P

D = 1 - P

Substitute \frac{1}{4} for P

D = 1 - \frac{1}{4}

Take LCM

D = \frac{4-1}{4}

D = \frac{3}{4}

<em>Hence, </em>1 - \frac{1}{4}<em> or </em>\frac{3}{4}<em> of the potting soil is Dirt</em>

7 0
3 years ago
What number adds to 25 but multiples to get 50
aleksandrvk [35]
Times two 25×2=50 thats the answer
3 0
3 years ago
15 yard =how many feet
yaroslaw [1]
Each yard is 3 feet, so
15•3= 45 feet
3 0
3 years ago
Read 2 more answers
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