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zaharov [31]
3 years ago
14

Can anyone help me with this?

Mathematics
2 answers:
Anna35 [415]3 years ago
6 0
The answer is B the second one
vivado [14]3 years ago
4 0
The answer is the second one
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Jonathan fills 2/5 of a toffe box in 15 seconds. How many boxes can he fill in 10 minutes?
Zina [86]

Answer:

16 boxes in 10 minutes

Step-by-step explanation:

2/5 = 15 sec

15 ÷ 2=7.5              1/5 = 7.5 seconds

7.5 × 5 = 37.5            37.5 = 1 box

60 × 10 = 600 secs

600 ÷ 37.5 = 16

16 boxes of toffee were made in 10 minutes

8 0
3 years ago
The point slope form of an equation of the line that passes through (-4, -3) and (12, 1) is y -1 =1/4(x-12). What is the standar
luda_lava [24]

The standard form: Ax + By = C.

We have:

y-1=\dfrac{1}{4}(x-12)\qquad|\text{multiply both sides by 4}\\\\4y-4=x-12\qquad|\text{add 12 to both sides}\\\\4y+8=x\qquad|\text{subtract 4y from both sides}\\\\8=x-4y

<h3>Answer: x - 4y = 8</h3>
6 0
3 years ago
SOMEONE PLEASE HELP<br> find the greatest common factor <br> 14g5h2, 56g3h4, 77g3h2
andrezito [222]

Answer:

\large\boxed{GCF(14g^5h^2,\ 56g^3h^4,\ 77g^3h^2)=g^3h^2}

Step-by-step explanation:

14g^5h^2=2\cdot7\cdot \boxed{g}\cdot \boxed{g}\cdot \boxed{g}\cdot g\cdot g\cdot \boxed{h}\cdot \boxed{h}\\\\56g^3h^4=2\cdot2\cdot2\cdot7\cdot\boxed{g}\cdot \boxed{g}\cdot \boxed{g}\cdot \boxed{h}\cdot \boxed{h}\cdot h\cdot h\\\\77g^3h^2=7\cdot11\cdot\boxed{g}\cdot \boxed{g}\cdot \boxed{g}\cdot \boxed{h}\cdot \boxed{h}\\\\GCF(14g^5h^2,\ 56g^3h^4,\ 77g^3h^2)=\boxed{g}\cdot \boxed{g}\cdot \boxed{g}\cdot \boxed{h}\cdot \boxed{h}=g^3h^2

8 0
3 years ago
Miss Berk has 8 pairs of pajama pants and 3 pairs of slippers. Three pairs of the pajama pants are Harry Potter themed and one p
shusha [124]

The probability that both items will be Harry Potter themed is 1/8.

<u>Step-by-step explanation:</u>

Total Number of pajama pants n(P) =8

Total number of slippers n(S)= 3

Number of Harry Potter themed Pajama pants n(H.P)=3

Number of Harry Potter themed slippers n(H.S)=1

We have to determine the probability of selecting pants and slippers that are both Harry Potter themed.

If two events A and B are independent, then the probability of A and B is given by

P(A and B)=P(A)*P(B)

Here the events selecting Harry potter themed pants and selecting harry Potter themed slippers are independent.

P(Harry\ Potter\ pants)=\frac{n(H.P)}{n(P)}

                                       =\frac{3}{8}

P(Harry\ Potter\ slippers)=\frac{n(H.S)}{n(S)} \\                                         =1/3

P(Harry\ Potter\ pants\ and\ Harry\ Potter\ slippers)=P(Harry Potter pants)\times P(Harry potter slippers)

=\frac{3}{8}\times  \frac{1}{3} =\frac{1}{8}

Hence probability of selecting Harry potter themed pants and Harry potter themed slippers is 1/8

3 0
3 years ago
Read 2 more answers
I need help on my math
ehidna [41]
It would be (A) because all the points match the numbers above it
4 0
3 years ago
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