Answer:
Step-by-step explanation:
Given
Shopper pushes a cart 50 m south down then turns 90 ^{\circ} west and moves 23 m.
he then makes
turn and moves 14 m
(a)Largest possible displacement is when he turns towards south
Net displacement![=\sqrt{64^2+23^2}=68.0 m](https://tex.z-dn.net/?f=%3D%5Csqrt%7B64%5E2%2B23%5E2%7D%3D68.0%20m)
(b)Smallest displacement when he turns towards north
![=\sqrt{36^2+23^2}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B36%5E2%2B23%5E2%7D)
![=\sqrt{1825}=42.72 m](https://tex.z-dn.net/?f=%3D%5Csqrt%7B1825%7D%3D42.72%20m)
KE=1/2(m)(v)^2
KE=1/2(80)(1.5)^2
KE=90 J
Answer:
a/(b+c)=h
Step-by-step explanation:
a=h(b+c)
a/(b+c)=h
Just one step.