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densk [106]
2 years ago
8

Henry will need a total of 15 pints of paint. The 3 pints of yellow were multiplied by 3 to get 9 total, so 2 pints of red would

be multiplied by 3 to get 6 total.
Which ideas did you include in your response? Check all that apply.
Henry will need 15 pints altogether.
The number of pints of yellow (3) is multiplied by 3 to get 9, so he would multiply 2 by 3 to get 6 pints of red.
Add: 6 + 9 = 15 pints.
Mathematics
1 answer:
bonufazy [111]2 years ago
4 0

Answer:

All answers are correct.

Step-by-step explanation:

Henry needs a total of 15 pints.

3 pints of yellow multiplied by 3 gives 9 pints of yellow, he needs 6 pints of red to get to 15, so he multiplies 2 pints of red by 3 to get 6 pints of red.

You add 9 + 6 to get the total of 15 pints he needs.

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47

Step-by-step explanation:

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3 years ago
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Mice21 [21]

Answer:

<em>LCM</em> = 8y^{4}(y+ 10)^{2}(y + 8)

Step-by-step explanation:

Making factors of 8y^{6}+ 144y^{5}+ 640y^{4}

Taking 8y^{4} common:

\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)

Using <em>factorization</em> method:

\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times  4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)

Now, Making factors of 2y^{4} + 40y^{3} + 200y^{2}

Taking 2y^{2} common:

\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)

Using <em>factorization</em> method:

\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10)        ............ (2)

The underlined parts show the Highest Common Factor(HCF).

i.e. <em>HCF</em> is 2y^{2} (y+ 10).

We know the relation between <em>LCM, HCF</em> of the two numbers <em>'p' , 'q'</em> and the <em>numbers</em> themselves as:

HCF \times LCM = p \times q

Using equations <em>(1)</em> and <em>(2)</em>: \Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times  4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times  4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)

Hence, <em>LCM</em> = 8y^{4}(y+ 10)^{2}(y + 8)

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3 years ago
A polymer is manufactured in a batch chemical process. Viscosity measurements show that it is approximately normally distributed
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Answer: (751.05, 766.95)

Step-by-step explanation:

We know that the confidence interval for population mean is given by :-

\overline{x}\pm z*\dfrac{\sigma}{\sqrt{n}},

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\overline{x}= sample mean

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Given :  \sigma= 20

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Now, the 99% confidence interval around the true population mean viscosity :-

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