Using the TI-83 family, TI-84 Plus family and TI-Nspire in TI-84 Plus mode classified as graphing calculators. There is an infinity symbol stipulated in these calculators. <span>An alternate method is inputting +</span><span>1E99 for positive infinity and -1E99 for negative infinity. This is the closest value to infinity.</span>
Answer:
Step-by-step explanation:
Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?
Let p(x)=kpx+dp and q(x)=kqx+dq than
f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7
p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7
(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)
So you want:
−2kpk2q=0
and
kpkq=−1
and
2kpd2p−3kpdq+7=0
Now I amfraid this doesn’t work as −2kpk2q=0 that either kp or kq is zero but than their product can’t be anything but 0 not −1 .
Answer: there are no such linear functions.
Randomly select a chip from a bucket containing eight chips, whick are each uniquely labeled with each child's name
In simplified form it is 5x+5
♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️


Thus :
1 / 4 % of 3 is 0.75 .
♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️