Let f(x) = log(x^2 + 1), g(x) = 10 – x^2, and R be the region bounded by the graphs of f and g, as shown above.

What is 5,729 + 2,729

Kazeer [188]

Answer:

it equals 8458

Step-by-step explanation:

Caculator

7 0

3 years ago

A report on consumer financial literacy summarized data from a representative sample of 1,663 adult Americans. Based on data fro

Tom [10]

Answer:

a) 95% Confidence interval = (0.536, 0.584)

This means that we are 95% confident that between 53.6% and 58.4% of Americans would give themselves grade of A or B on their financial knowledge of personal finance.

b) The result of the 95% confidence interval agrees with the claim that majority of Americans would give themselves a grade of A or B on their financial knowledge of personal finance because the interval obtained for possible values that the population proportion of Americans that would give themselves a grade of A or B on their financial knowledge of personal finance lies completely on the side that is greater than a proportion of 0.50 which indicates that truly, majority of Americans would give themselves a grade of A or B on their financial knowledge of personal finance.

Step-by-step explanation:

Confidence Interval for the population proportion is basically an interval of range of values where the true population proportion can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample proportion) ± (Margin of error)

Sample proportion = proportion of Americans in the sample that would give themselves grade of A or B on their financial knowledge of personal finance = p = (934/1663) = 0.56

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error)

Critical value at 95% confidence interval for sample size of 1663 is obtained from the z-tables as the sample size is large enough for the sample properties to approximate the population properties.

Critical value = 1.960 (from the z-tables)

Standard error of the mean = σₓ = √[p(1-p)/n]

p = 0.56

n = sample size = 1663

σₓ = √[0.56×0.44/1663] = 0.0121723457 = 0.01217

95% Confidence Interval = (Sample proportion) ± [(Critical value) × (standard Error)]

CI = 0.56 ± (1.96 × 0.01217)

CI = 0.56 ± 0.0238532

95% CI = (0.5361468, 0.5838532)

95% Confidence interval = (0.536, 0.584)

b) The result of the 95% confidence interval agrees with the claim that majority of Americans would give themselves a grade of A or B on their financial knowledge of personal finance because the interval obtained for possible values that the population proportion of Americans that would give themselves a grade of A or B on their financial knowledge of personal finance lies completely on the side that is greater than a proportion of 0.50 which indicates that truly, majority of Americans would give themselves a grade of A or B on their financial knowledge of personal finance.

Hope this Helps!!!

5 0

3 years ago

If in an equation the variables cancel out while solving and u are left with a true statement how many solutions are there and i

Deffense [45]

Answer: infinitely many and none

Step-by-step explanation:

if all variables cancel and you are left with zero, there are infinitely many solutions. if it is false there are no solutions.

4 0

3 years ago

Read 2 more answers

The probability that a randomly selected 2 2-year-old male garter snake garter snake will live to be 3 3 years old is 0.98861 0

Mnenie [13.5K]

Answer:

a. $Probability = 0.97735$

b. $Probability = 0.92294$

c. $P(At\ Least\ One) = 1$

No, it is not unusual if at least 1 lives up to 3.

Step-by-step explanation:

Given

Represent the probability that a 2 year old snake will live to 3 with P(Live);

$P(Live) = 0.98861$

Solving (a): Probability that two selected will live to 3 years.

Both snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

$Probability = P(Live)\ and\ P(Live)$

$Probability = 0.98861 * 0.98861$

$Probability = 0.9773497321$

$Probability = 0.97735$ <em>--- Approximated</em>

Solving (b): Probability that seven selected will live to 3 years.

All 7 snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

$Probability = P(Live)^n$

Where $n = 7$

$Probability = 0.98861^7$

$Probability = 0.92294324145$

$Probability = 0.92294$ <em>--- Approximated</em>

Solving (c): Probability that at least one of seven selected will not live to 3 years.

In probabilities, the following relationship exist:

$P(At\ Least\ One) = 1 - P(None).$

So, first we need to calculate the probability that none of the 7 lived up to 3.

If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861

This gives:

$P(Not\ Live) = 0.01139$

The probability that none of the 7 lives up to 3 is:

$P(None) = P(Not\ Live)^7$

$P(None) = 0.01139^7$

Substitute this value for P(None) in

$P(At\ Least\ One) = 1 - P(None).$

$P(At\ Least\ One) = 1 - 0.01139^7$

$P(At\ Least\ One) = 0.99999999999997513055642436060443621$

$P(At\ Least\ One) = 1$ ---- Approximated

No, it is not unusual if at least 1 lives up to 3.

This is so because the above results, which is 1 shows that it is very likely for at least one of the seven to live up to 3 years

7 0

3 years ago

Find the mean, median, and mode of the data, if possible. If any of these measures cannot be found or a measure does not repre

Contact [7]

Answer:

1. Median = 10.1

2. A. The median represents the center.

3. D. The mode(s) can't represent the center because it (they) is(are) not a data value.

Step-by-step explanation:

Mean of a sample = sum of the samples/no of the samples

Samples in increasing order:

9.8

9.9

10.1

10.4

10.6

11.1

Mode is the sample with highest frequency.

Median is the middle entry of the data.

Mean = (9.8 + 9.8 + 9.9 + 10.1 + 10.4 + 10.6 + 11.1)/7

= 717/7

= 10.243

Median = 10.1

Mode = 9.8 because it has the highest frequency of 2

6 0

4 years ago