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ANTONII [103]
3 years ago
8

if any one can help me that would be awesome 1. − 8 = 5 b − 3 b 2. k − 8 + 6 k = 20 3. 723. 4. 6 ( 3 + 3 x ) = 72 364. 5 ( m + 4

) − m = 36
Mathematics
1 answer:
Morgarella [4.7K]3 years ago
5 0

Answer:

1)b=-4

2)k=4

3)can u explain what #3 and 4 say

4)?

5)0/ no solution

Step-by-step explanation:

You might be interested in
given the following information, determine which lines, if any, are parallel. state the converse that justifies your answer.
frozen [14]

From the information in the diagram found in a similar question online (please see attached drawing), the parallel lines are;

  1. w||z
  2. x||y
  3. x||y
  4. w||z
  5. w||z
  6. x||y
  7. x||y
  8. w||z
  9. x||y
  10. w||z

<h3>What are the relationships between angles formed by parallel lines?</h3>

Parallel lines are lines that do not meet, when extended indefinitely.

The possible information given as obtained from a similar question posted online are;

1. ‹1 is congruent to ‹5

2. ‹7 is congruent to ‹9

3. m‹8 + m‹9 = 180°

4. ‹16 is congruent to ‹14

5. m‹1 + m‹4 = 180°

6. ‹3 is congruent to ‹13

7. ‹2 is congruent to ‹10

8. ‹11 is congruent to ‹15

9. m‹4 + m‹13 = 180°

10. ‹8 is congruent to ‹6

1. Given that ‹1 is congruent to ‹5 where ‹1 and ‹5 are alternate exterior angles, we have that line <em>w </em>is parallel to line <em>z </em>

  • w||z

Theorem (converse); Alternate exterior angles formed by two parallel lines having a common transversal are congruent.

2. ‹7 and ‹9 are alternate interior angles.

Given that ‹7 is congruent to ‹9, therefore;

Line <em>x</em> is parallel to line <em>y</em>

  • x||y

Theorem (converse); Alternate interior angles formed by two parallel lines having a common transversal are congruent.

3. Given that m‹8 + m‹9 = 180°, therefore;

‹8 and ‹9 are supplementary angles, formed between lines <em>x </em>and <em>y</em>.

‹8 and ‹9 are also consecutive interior angles.

Theorem (converse); Consecutive interior angles formed between parallel lines are supplementary.

Therefore;

  • x||y

4. ‹16 and ‹14 are corresponding angles formed by lines <em>w </em>and <em>z</em>.

Theorem (converse); Corresponding angles formed by parallel lines are congruent.

Given ‹16 congruent to ‹14, we have;

  • w||z

5. m‹1 and m‹4 are consecutive exterior angles formed by lines <em>w </em>and <em>z</em>.

Theorem (converse); Consecutive exterior angles formed by two parallel lines are supplementary.

Given that m‹1 + m‹4 = 180°, we have;

  • w||z

6. ‹3 and ‹13 are alternate exterior angles formed by lines <em>x </em>and <em>y</em>.

Theorem (converse); Alternate exterior angles formed by parallel lines are congruent.

Given that ‹3 congruent to ‹13, we have;

  • x||y

7. ‹2 and ‹10 are corresponding angles formed by lines <em>x </em>and <em>y</em>

Given that ‹2 congruent to ‹10, therefore;

  • x||y

8. ‹11 and ‹15 are alternate interior angles formed by lines <em>w </em>and <em>z</em>.

‹11 is congruent to ‹15, therefore;

  • w||z

9. ‹4 and ‹13 are consecutive exterior angles formed by lines <em>x </em>and <em>y</em>

m‹4 + m‹13 = 180°, therefore;

  • x||y

10. ‹8 and ‹6 are corresponding angles formed by lines <em>w </em>and <em>z</em>.

‹8 is congruent to ‹6, therefore;

  • w||z

Learn more about angles formed by parallel lines that have a common transversal here:

brainly.com/question/24607467

#SPJ1

3 0
1 year ago
Find the linear equation of the plane through the origin and the points (5,2,2) and (6,−1,1). equation:
Aleks [24]
The cross of the position vectors is
.. [5, 2, 2] × [6, -1, 1] = [4, 7, -17] . . . . . the normal vector of the desired plane

Since the origin is a point in the plane, its equation can be written as
.. 4x +7y -17z = 0
3 0
4 years ago
6 1/6 6 1/3 6 2/3 6 3/2
Vladimir [108]

Given:

The expression is

\sqrt{\sqrt[3]{6}}

To find:

The simplified form of the given expression.

Solution:

We have,

\sqrt{\sqrt[3]{6}}

Using the properties of radical and exponent, we get

=(\sqrt[3]{6})^{\frac{1}{2}}                     [\because \sqrt{x}=x^{\frac{1}{2}}]

=\left(6^{\frac{1}{3}}\right)^{\frac{1}{2}}                  [\because \sqrt[n]{x}=x^{\frac{1}{n}}]

=6^{\frac{1}{3}\times\frac{1}{2}}                    [\because (a^m)^n=a^{mn}]

=6^{\frac{1}{6}}

Therefore, the correct option is A.

8 0
3 years ago
Pls answer the question below
Lorico [155]
<h3>Answer :</h3>

After dividing by 4, the resultant is still a polynomial because it still has more than two algebraic terms which have different powers.

3 0
3 years ago
Read 2 more answers
I need help with number 5
GREYUIT [131]
The domain is all the ones under the x and the range are the numbers under the y (that goes fo any question like that)
5 0
3 years ago
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