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3 years ago

How can these requirements be met, assuming the organization-wide default for projects is set to private?

Computers and Technology

1 answer:

Papessa [141]3 years ago

7 0

Answer:

The answer is "Option B and C".

Explanation:

Universal Containers is a fast-growing multinational product distributor, in which the company creates all types of boxes including basic postal to customized machinery manufacturing to large tanks for shipment delivery, in which both options a and b were correct that can be described as follows:

In this connection was based on distribution criteria, that uses the agency of Program, which gives users access via roles, and all the distribution rules based on parameters, which gives public organizations exposure to members, and wrong choices can be described as follows:
In options A and option D both were wrong because it is not based on criteria, that's why it can't allow you access.

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Write a program that reads the contents of the two files into two separate lists. The user should be able to enter a boy’s name,

insens350 [35]

Answer:

Check Explanation.

Explanation:

A programming language is used by engineers, technologists, scientists or someone that learnt about programming languages and they use these programming languages to give instructions to a system. There are many types for instance, c++, python, Java and many more.

So, the solution to the question above is given below;

#define the lists

boyNames=[]

girlNames=[]

#open the text file BoyNames.txt

with open('BoyNames.txt','r') as rd_b_fl:

boyNames=rd_b_fl.readlines()

boyNames=[name.strip().lower() for name in boyNames]

#open the text file GirlNames.txt

with open('GirlNames.txt','r') as rd_b_fl:

girlNames=rd_b_fl.readlines()

girlNames=[name.strip().lower() for name in girlNames]

#print the message to prompt for name

print('Enter a name to see if it is a popular girls or boys name.')

while True:

#prompt and read the name

name=input('\nEnter a name to check, or \"stop\" to stop: ').lower()

# if the input is stop, then exit from the program

if name=='stop':

break

# If the girl name exits in the file,then return 1

g_count=girlNames.count(name)

# if return value greater than 0, then print message

if g_count>0:

print(name.title()+" is a popular girls name and is ranked "

+str(girlNames.index(name)+1))

# if return value greater than 0, then print message

#"Not popular name"

else:

print(name.title()+" is not a popular girls name")

## If the boy name exits in the file,then return 1

b_count=boyNames.count(name)

if b_count>0:

print(name.title()+" is a popular boys name and is ranked "

+str(boyNames.index(name)+1))

# if return value greater than 0, then print message

#"Not popular name"

else:

print(name.title()+" is not a popular boys name")

3 0

3 years ago

What was the first Apple computer, and who was it designed by?

DerKrebs [107]

Answer: The first Apple Computer was Apple 1. The designer was Steve Wozniak.

Explanation: Steve Wozniak and Steve Jobs both created Apple 1. Mainly, Steve Wozniak designed it.

Hope this helps!

7 0

3 years ago

Read 2 more answers

Three IT Companies. Help me please!

GuDViN [60]

Answer:

Apple, Samsung and Foxconn

Explanation:

They are the leading it companies today

3 0

3 years ago

Read 2 more answers

In JAVA, answer the following:

erica [24]

Answer:

The JAVA program is as follows.

import java.util.Scanner;

public class Program

{

static int n;

public static void main(String[] args) {

//scanner object

Scanner stdin = new Scanner(System.in);

//loop executes till number entered is in the range of 1 to 10

{

System.out.print("Enter any number: ");

n = stdin.nextInt();

}while(n<1 || n>10);

System.out.println("Number is valid. Exiting...");

}

OUTPUT

Enter any number: 0

Enter any number: 23

Enter any number: 10

Number is valid. Exiting...

Explanation:

The program is explained.

1. The integer variable, n, is declared static since the variable should be accessible inside main() which is static.

2. An object of Scanner, stdin, is created inside main().

3. Inside do-while loop, the user is asked input any value for n.

4. The loop continues till user inputs a number which is not in the given range, beginning from 1 to 10.

5. The loop will not be terminated till the user enters a valid input.

6. Once a valid input is entered, the message is displayed to the console and the program ends.

7. The variable, n, is declared at the class level and is a class variable. Class variables are declared inside the class but outside all the methods in that class.

8. Since JAVA is a purely object-oriented language, all the code is written inside class.

9. The object of class is not created since only one class is included in the program. If more than one class is included, then the object of the class which does not has the main() method will be created inside main().

10. User input for integer is taken via scanner object and using nextInt() method.

11. The methods, print() and println() display the messages to the console. The only difference is that println() inserts a new line after displaying the message.

12. The name of the class having main() and the name of the program should be the same.

7 0

3 years ago

When an instance of a class, or object, is specified as a parameter to a method, a reference to the said object is passed to the

OLEGan [10]

Or pointer

VERY similar.

5 0

3 years ago