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sveticcg [70]
3 years ago
7

Which point on the number line shows the graph of

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
7 0
The answer is K, -3!

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11. Crítique Reasoning Jaime wrote
Umnica [9.8K]

Answer:No

Step-by-step explanation: 4.4 - 0.33 = 4.07 so there is no reasoning for it to be 1.1 since it make no sense at all.

5 0
3 years ago
How many Solutions does this system have? (1 point)
mixas84 [53]

The given system of equation that is 2x+y=3 and 6x=9-3y has infinite number of solutions.

Option -C.

<u>Solution:</u>

Need to determine number of solution given system of equation has.

\begin{array}{l}{2 x+y=3} \\\\ {6 x=9-3 y}\end{array}

Let us first bring the equation in standard form for comparison

\begin{array}{l}{2 x+y-3=0} \\\\ {6 x+3 y-9=0}\end{array}

\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}}

To check how many solutions are there for system of equations a_{1} x+b_{1} y+c_{1}=0 \text{ and }a_{2} x+b_{2} y+c_{2}=0, we need to compare ratios of \frac{a_{1}}{a_{2}}, \frac{b_{1}}{b_{2}} \text { and } \frac{c_{1}}{c_{2}}

In our case,  

a_{1} = 2, b_{1}= 1\text{ and }c_{1}= -3

a_{2}  = 6, b_{2} = 3,\text{ and }c_{2} = -9

\begin{array}{l}{\Rightarrow \frac{a_{1}}{a_{2}}=\frac{2}{6}=\frac{1}{3}} \\\\ {\Rightarrow \frac{b_{1}}{b_{2}}=\frac{1}{3}} \\\\ {\Rightarrow \frac{c_{1}}{c_{2}}=\frac{-3}{-9}=\frac{1}{3}} \\\\ {\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}=\frac{1}{3}}\end{array}

As \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}, so given system of equations have infinite number of solutions.

Hence, we can conclude that system has infinite number of solutions.

5 0
3 years ago
Show work on how to do it
svetlana [45]

Answer:

3 steps rotations

Step-by-step explanation:di ko sigurado

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2 years ago
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They could look at the weight(take into consideration if the book is paperback or hardcover), the length, and the size of the font to estimate the size of the book. 
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Which of the following statements is true of chords?
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All of those are true, except the one about the radius.  Because alternate definition of diameter uses the idea of chord. So, both ends of a chord have to be on the circle, but one end of a radius is at the center, so a radius can't be a chord.
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