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3 years ago

Moving forward a negative distance is the same as moving backward a positive distance.

1 answer:

6 0

The answer is: False, because, by definition, the distance (which is a scalar quantity) is the absolute value of the displacement. This means that the distance cannot be negative, but the displacement (which is define as a vector quantity can be positive or negative.

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If 8 boxes of crayons cost $20 , what would 6 boxes cost ?

Y_Kistochka [10]

Answer:

$15

Step-by-step explanation:

To figure thsi out, you do 20 divided by 8, which gives you 2.5 ($2.50.)

Next you do 2.50 x 6 which gives you 15 ($15.)

The answer is $15.

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6 0

3 years ago

Stephen makes wooden shelves for his room he starts with a board that is 20 feet long.Stephen wants to make the shelves 3/4 foot

jek_recluse [69]

The number of shelves stephen can make is approximately 27

<h3><u>Solution:</u></h3>

Given that Stephen makes wooden shelves for his room

Stephen wants to make the shelves 3/4 foot long

He starts with a board that is 20 feet long

To find: number of shelves he can make

So the number of shelves stephen can make can make is found out by dividing 20 feet long board by 3/4 foot long

$\text {number of shelves }=\frac{\text { total length of board stephen has }}{\text { length of each board }}$

$\text {number of shelves }=\frac{20}{3 / 4}=\frac{20}{0.75}=26.6$

So the number of shelves stephen can make is approximately 27

3 0

3 years ago

The sum of the diagonals of a rhombus is 5√2.

Alex

Greetings!
Let ABCD be a rhombus
AC + BD = 5√2 cm

Area of ABCD = Ar△ABD + Ar △BCD
$= \frac{1}{2} \times BD \times AO + \frac{1}{2} \times BD \times OC$
$= \frac{1}{2} BD (AO + OC)$
$\frac{1}{2} BD \times AC$

$So, \frac{ BD \times AC}{2} = 4 \: cm {}^{2}$
$BD \times AC = 8$
$Now, AC + \: BD = 5 \sqrt{2}$

Squaring both sides, we get
$AC {}^{2} + BD {}^{2} + 2 AC.BD =50$
$AC {}^{2} + BD {}^{2} + 2 \times 8 = 50$
$AC {}^{2} + BD {}^{2} = 50 - 16$
$AC {}^{2} + BD {}^{2} = 34$

In △AOB, we have
$OA {}^{2} + OB {}^{2} =AB {}^{2}$
$( \frac{ AC }{2} ) {}^{2} + ( \frac{ BD}{2} ) {}^{2} = AB {}^{2}$
$\frac{ AC {}^{2} } {4} + \frac{ BD {}^{2} }{4} = AB {}^{2}$
$AC {}^{2} + BD {}^{2} = 4 AB {}^{2}$
$34 = 4 AB {}^{2}$

Square rooting both sides
$\sqrt{34} = 2 AB$
$Perimeter = 4 \: AB \\ = 2 \times 2 \: AB \\ = 2 \: \times \sqrt{34 } \\ = 2 \sqrt{34 \: } units$ .

Hope it helps!

7 0

3 years ago

Help with math word problem, 10 points

Feliz [49]

I hope this helps you

6 0

3 years ago

Below are two parallel lines with a third line intersecting them.

andrew-mc [135]

Answer:

132 degrees

Step-by-step explanation:

One sit of the 48 degrees is 48 degrees, so that opposite will be the same. Add them up, get 96. There is a full 360 degrees circle, so get 360 and subtract 96 from it, to get 264 degrees. That is the top and bottom angle of the right side, so just divide it in two

4 0

3 years ago

Read 2 more answers