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4 years ago

What is the area of the triangle shown below? 8 height width 10

Mathematics

2 answers:

kvasek [131]4 years ago

7 0

Answer:

40 units^2

Step-by-step explanation:

lakkis [162]4 years ago

3 0

The formula for the area of a triangle is A = 1/2 * b * h.

Using this formula, we can plug in the base (b) and height (h) and solve for the area.

A = (0.5)(8)(10)

A = 4 x 10

A = 40 units^2

Hope this helps!! :)

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KonstantinChe [14]

Answer:

Choice C

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Step-by-step explanation:

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Using identity 1, we can solve for cos(s) and cos(t)

$sin(s)=-\frac{\sqrt{3}}{3}, sin^{2}(s)=\frac{3}{9}=\frac{1}{3}\\cos^{2}(s)=1-sin^{2}(s)=1-\frac{1}{3}=\frac{2}{3}; cos(s)=\pm\sqrt{\frac{2}{3}}\\\\$

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Since both angles lie in quadrant IV, both cos(s) and cos(t) must be positive so we only consider the positive signs of both values

Using identity 2, we can solve for cos(s-t)

$cos(s-t)=cos(s)cos(t)+sin(s)sin(t)=\frac{\sqrt{2}}{\sqrt{3}}.\frac{\sqrt{31}}{6}+(-\frac{\sqrt{3}}{3})(-\frac{\sqrt{5}}{6})$

Multiplying numerator and denominator of the first term by $\sqrt{3}$ gives us the final expression as

$\frac{\sqrt{3}}{\sqrt{3}}\frac{\sqrt{2}}{\sqrt{3}}.\frac{\sqrt{31}}{6}+(-\frac{\sqrt{3}}{3})(-\frac{\sqrt{5}}{6})=\frac{\sqrt{186}}{18}+\frac{\sqrt{15}}{18}= \frac{\sqrt{186}+\sqrt{15}}{18}$

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