Answer: The female had the genotype XHXh, and produced the two gametes seen at the left side of the diagram. The male had the genotype XHY0, and produced the two gametes seen at the right side of the diagram.
Explanation:
Answer:
The "tail" of the molecule is made up of two fatty acids, which are hydrophobic and do not dissolve in water. Following the rule of "like dissolves like", the hydrophilic head of the phospholipid molecule dissolves readily in water.
Nonpolar Fatty Acids
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1. Mitosis takes place within somatic cells (cells that make up the body). Meiosis takes place within gamete cells (sex cells).
2. One single division of the mother cell results in two daughter cells. Two divisions of the mother cell result in four meiotic products or haploid gametes.
3. A mitotic mother cell can either be haploid or diploid. A meiotic mother cell is always diploid.
4. The number of chromosomes per nucleus remains the same after division. The meiotic products contain a haploid (n) number of chromosomes in contrast to the (2nd) number of chromosomes in the mother cell.
5. It is preceded by an S-phase in which the amount of DNA is duplicated. In meiosis, only meiosis I is preceded by an S-phase.
6. In mitosis, there is no pairing of homologous chromosomes. During prophase I, complete pairing of all homologous chromosomes takes place.
7. There is no exchange of DNA (crossing-over) between chromosomes. There is at least one crossing-over or DNA exchange per homologous pair of chromosomes.
8. The centromeres split during anaphase. The centromeres do separate during anaphase II, but not during anaphase I.
9. The genotype of the daughter cells is identical to that of the mother cells. Meiotic products differ in their genotype from the mother cell.
10. After mitosis, each daughter cell has exactly same DNA strands. After meiosis, each daughter cell has only half of the DNA strands
Answer and Explanation:
Ello mate here's your answer!
Monosaccharides are also known as <em><u>simple sugars.</u></em>
Answer:
Genotype & Phenotype
BbFf - 4
bbFf - 4
Bbff - 4
bbff- 4
Phenotype
BbFf – Black Hair with six fingers
bbFf – red hair with six fingers
Bbff – Black hair with five fingers
Bbff – red hair with five fingers
Explanation:
Given
Black hair allele is represented by "B"
Red hair allele is represented by "b"
Trait of having six fingers is represented by "F"
Trait of having five fingers is represented by "f"
Also , B is dominant over b and F is dominant over f
Genotype of sally having black hair and five fingers when her father has red hair is Bbff
Genotype fo Bill having red hair and six fingers when his mother had five fingers is bbFf
Bbff * bbFf
Bf bf Bf bf
bF BbFf bbFf BbFf bbFf
bf Bbff bbff Bbff bbff
bF BbFf bbFf BbFf bbFf
bf Bbff bbff Bbff bbff
Genotype & Phenotype
BbFf - 4
bbFf - 4
Bbff - 4
bbff- 4
Phenotype
BbFf – Black Hair with six fingers
bbFf – red hair with six fingers
Bbff – Black hair with five fingers
Bbff – red hair with five fingers
