Answer:
A) Bacteria cannot carry out RNA splicing to remove introns and so produced a much larger protein.
Explanation:
Human is a eukaryote and has both introns and exons in its genes. Transcription of human genes forms a primary transcript that undergoes post-transcriptional modification.
One of the important even during the post-transcriptional modification is the removal of introns and joining the exons together to make a mature mRNA which in turn serves as the template for protein synthesis.
<em>E. coli</em> is a prokaryote and does not have the enzymatic machinery required for the splicing of introns.
Cloning of a complete human gene into the <em>E. coli</em> cells would not form the respective human protein since the bacterial cells would not be able to splice the introns from the primary transcript.
Answer:
<h2>RrYy and rryy
</h2>
Explanation:
1. As given; Round seeds (R) are dominant on wrinkled seeds (r),
Yellow seeds (Y) are dominant on green seeds (g).
In a testcross, between an unknown genotype and a homozygous recessive with wrinkled and green seeds (rryy).
offspring are:
Round and yellow are 53; genotype (R_Y_)
round and green are 49; genotype (R_yy)
wrinkle and yellow are 44; genotype (rrY_)
wrinkled and green are 51 ; genotype (rryy)
Here, the genotype of parents of these offspring would be RrYy and rryy.
The correct answer is: daughter cells will have abnormal chromosome numbers and this condition is called aneuploidy.
Nondisjunction is the failure of homologous chromosomes (or sister chromatids) to separate during the process of cell division and consequently lead to aneuploidy. There are three forms of nondisjunction:
• Nondisjunction in meiosis I (pair of homologous chromosomes unable to separate in meiosis I),
• Nondisjunction in meiosis I (sister chromatids unable to separate during meiosis II), and
• Nondisjunction in mitosis (failure of sister chromatids to separate during mitosis)
