Answer:
M phase: 4.8 hr
Prophase: 2.4 hr
Prometaphase: 0.72 hr
Metaphase: 0.24 hr
Anaphase: 0.84 hr
Telophase: 0.6 hr
Explanation:
Mitosis, also known as M phase, is the process of nuclear division after interphase, which is followed by cytoplasmic division via cytokinesis. Mitosis can be subdivided into the following phases: Prophase, Prometaphase, Metaphase, Anaphase, and Telophase. In this case, 160 cells are in interphase (for a total of 200 cells), thereby 40 cells are in mitosis >> 200 - 160 = 40 cells. Since the complete cell cycle requires 24 hours, it is possible to calculate the average duration of each phase:
M phase: 40/200 = 0.2 x 24 hr = 4.8 hr
Prophase: 20/200 = 0.1 x 24 hr = 2.4 hr
Prometaphase: 6/200 = 0.030 x 24 hr = 0.72 hr
Metaphase: 2/200 = 0.01 x 24 hr = 0.24 hr
Anaphase: 7/200 = 0.035 x 24 hr = 0.84 hr
Telophase: 5/200 = 0.025 x 24 hr = 0.6 hr
Answer:
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Explanation:The concentration of a solution can be given in moles of solute dissolved per kilogram of solvent.
This is known as molality.
(Not to be confused with molarity which is a different measure of concentration.)
Molality is given the symbol m.
molality = moles of solute ÷ mass of solvent in kilograms
m = n(solute) ÷ mass(solvent in kg)
A solution containing 3 moles of solute per kilogram of solvent for example, is said to be 3-molal or 3m.
The correct answer is option C. A leaf growing in full sunlight
The chloroplast is an organelle, which helps the plants to carry out the process of the photosynthesis. The leaves are the main site of the photosynthesis in the plants, hence, they have an abundant number of chloroplasts present in the cells. In the presence of the sunlight, they perform the light dependent reactions of the photosynthesis process. In case, a scientist find out the cell, which have a high number of chloroplast, then the cell must be specialised to perform photosynthesis, hence, the cell would belong to the leaves, which are growing in full sunlight.
Answer:
Smaller unit in size as 1 centimeter equals to 10 millimeters.
