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horsena [70]
3 years ago
13

A regular nonagon has a radius of 18.8 cm. What is the length of the apothem? Round your answer to the nearest tenth.

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
6 0
C. 17.7 cm this is correct I just had this question on my work and this is the answer
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Explain the equasion how to get the answer to how 1/3 of a carton of eggs equals 4
user100 [1]
A carton of eggs is usually 1 dozen, which is 12 eggs. 1/3 of 12 is 4. You get 4 by multiplying 12 times 1/3.

=12(1/3)
=12/3
=4

Hope this helps! :)
4 0
3 years ago
Jamal recorded the daily high temperatures over a two week period
lorasvet [3.4K]

Answer:

A. 4

Step-by-step explanation:

First rearrange the temperatures from low to high

60, 65, 68, 69, 69, 70, 70, 70, 71, 71, 73, 74, 75, 77

There are 14 data,

Q1 = 4th data = 69

Q3 = 11th data = 73

Interquartile range = Q3 - Q1 = 73 - 69 = 4

5 0
2 years ago
1. What is the slope of the graph? (HINT: Pay close attention to what the x and y axes are counting by!) 2. What does the slope
lidiya [134]

Slope = -4/5

Jeremiah looses money every time he buys a ticket

hope this helped a little

6 0
3 years ago
5,9,4,5,7,1,3,6<br> What is the median?<br><br> A. 8<br> B. 1<br> C..5<br> D. 4.
Serhud [2]

Answer: The median is 5.

Step-by-step explanation: If you add all the numbers up, you get 40. There are 8 numbers, so 40 divided by 8 is 5.

5 0
3 years ago
Consider a t distribution with 7 degrees of freedom. Compute P(-1.29 &lt; t &lt; 1.29). Round your answer to at least three deci
ss7ja [257]

Answer:

a) 0.76197086

b) -1.73406361

Step-by-step explanation:

a)

Consider a t distribution with 7 degrees of freedom. Compute P(-1.29 < t < 1.29)

P(-1.29 < t < 1.29) would be the area under the t distribution curve with 7 degrees of freedom between -1.29 and 1.29, that is in the interval (-1.29, 1.29).

This can be done the old style by looking up in a table or by using the technology with a spreadsheet.

In Excel, the function TDIST(x,n,2) with x>0 gives the area outside the interval (-x, x) of the t distribution with n degrees of freedom.

So TDIST(1.29,7,2) gives the area outside (-1.29, 1.29).

If we subtract this value from 1 we get the desired result

Hence  

P(-1.29 < t < 1.29) = 1 - TDIST(1.29,7,2) = 1 - 0.23802914 = 0.76197086

In OpenOffice Calc, the function is the same replacing “,” with “;”  

That is

P(-1.29 < t < 1.29) = 1 - TDIST(1.29;7;2) = 0.76197086

b)

Consider a t distribution with 18 degrees of freedom. Find the value of c such that P(t≤ c) = 0.05

We are looking for a point c such that the area of the t distribution with 18 degrees of freedom to the left of c is 0.05

In Excel, the inverse function of TDIST is TINV.  

TINV(p*2,n) with p>0 gives the point c such that the area of the t distribution with n degrees of freedom to the right of c is p.  

Since <em>the t distribution is symmetric with respect to 0</em>, -c would be a point such that the area to the left of -c is p.

So we want to compute  in Excel

-TINV(0.05*2,18) = -1.73406361

In OpenOffice Calc  

-TINV(0.05*2;18) = -1.73406361

3 0
3 years ago
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