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dimulka [17.4K]
2 years ago
11

He starts the month with 12 puppets ready to sell, and make 14 puppets per day. Write an equation to model this situation (use d

for days and p for puppets)
Mathematics
1 answer:
Alex787 [66]2 years ago
5 0

Answer:

p = 12 + 14d

Step-by-step explanation:

puppets is equal to twelve times fourteen days

You might be interested in
(-9,5); m=4 right and equation in point slope form of the line that passes through the given point and with the given slope M
NikAS [45]

Answer:

Slope form of line  y = 4x +41

Step-by-step explanation:

m= 4

The y-intercept of the line that passes through the given point  (-9,5) is

5 = 4(-9) + b

b= 5 +36

b=41

The equation of the line that passes through the given point  (-9,5) is

y =mx +b

 y = 4x +41

6 0
2 years ago
The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6
viktelen [127]

Answer:

a)

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

b)

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5.

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders    No. contracts     Relative frequency of contracts

2                         6                       6/102=0.0588

3                         20                     20/102=0.1961

4                         24                     24/102=0.2353

5                         18                       18/102=0.1765

6                         13                        13/102=0.1275

7                          7                          7/102=0.0686

8                          5                          5/102=0.049

9                          6                          6/102=0.0588

10                         2                           2/102=0.0196

11                          1                            1/102=0.0098

Total                  102

a)

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

b)

We have to find proportion of contracts involved  between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved  strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10=  Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

8 0
3 years ago
B is the midpoint of ac. Ab = x+9 and bc = 3x-7 find x and ac
natali 33 [55]

To solve this problem, we need to know 2 relationships:

<h2>1. AC = AB + BC</h2>

The distance of AC is the sum of AB and BC.

AC = AB + BC

We know this since the distance of going from A to C (AC) is the same as going from A to B (AB), then B to C (BC).

<h2>2. AB = BC</h2>

The distance of AB is the same as AC.

AB = BC

We know this since B is in the middle of AC, so the distance from B to A (BA) is the same as the distance from B to C (BC).

You can see the attached image (at the bottom) for a visualization of this.

<h2>Putting them together</h2>

Since we know the values of AB and BC...

AB = x+9\\BC = 3x-7

...we can put these values into our 2nd equation and solve for x:

AB = BC\\x + 9 = 3x -7

Add 7 to both sides:

x + 16 = 3x

Subtract x from both sides:

16 = 2x

Divide both sides by 2:

8 = x\\x = 8

Knowing x, we can find the distance of AC using our first equation.

AC = AB + BC

Let's put in the values of AB and BC:

AC = (x+9) + (3x-7)

Before we put in x = 8, we can simplify this:

AC = (x+9) + (3x-7)\\AC = x + 9 + 3x -7\\AC = x + 3x + 9 -7\\AC = 4x + 9 - 7\\AC = 4x+2

We group x and 3x and add those together. Then we subtract 7 from 9.

With this equation, we can put in x = 8:

AC = 4x +2\\AC = 4*8 + 2

Since 4 * 8 = 32:

AC = 4 * 8 + 2\\AC = 32 + 2\\AC = 34

Finally, we have found both x and AC.

<h2>Answer</h2>

x = 8

AC = 34

7 0
3 years ago
Lindsey Smith was the top scorer in a women's professional basketball league for the 2006 regular season, with a total of 864 po
andreev551 [17]

Answer:

Number of 3 point goals = 85

Number of 2 point goals = 3(85) - 62 = 193

Number of free throws = 3(85)- 32 = 223

Step-by-step explanation:

Given that :

2 point goals

Number of 3 point goals = x

Number of 2 point goals = 3x - 62

Number of free throws = 3x - 62 - 30 = 3x - 32

3x + 2(3x - 62)+ 3x - 32= 864.

3x + 6x - 124 + 3x - 32 = 864

12x = 864+ 124 + 32

12x =1020

x = 1020 / 12

x = 85

Number of 3 point goals = 85

Number of 2 point goals = 3(85) - 62 = 193

Number of free throws = 3(85)- 32 = 223

3 0
2 years ago
Why are tenths, fifths, fourths, and halves easy<br> to express as percent?
Marysya12 [62]
Because they all go into 100 easily. for example 10×10=100 5×20=100
6 0
2 years ago
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