Answer:
1. When we reflect the shape I along X axis it will take the shape I in first quadrant, and then if we rotate the shape I by 90° clockwise, it will take the shape again in second quadrant . So we are not getting shape II. This Option is Incorrect.
2. Second Option is correct , because by reflecting the shape I across X axis and then by 90° counterclockwise rotation will take the Shape I in second quadrant ,where we are getting shape II.
3. a reflection of shape I across the y-axis followed by a 90° counterclockwise rotation about the origin takes the shape I in fourth Quadrant. →→ Incorrect option.
4. This option is correct, because after reflecting the shape through Y axis ,and then rotating the shape through an angle of 90° in clockwise direction takes it in second quadrant.
5. A reflection of shape I across the x-axis followed by a 180° rotation about the origin takes the shape I in third quadrant.→→Incorrect option
Answer:
Graph D
Step-by-step explanation:
it does not pass the linear test to qualify as a function
Answer:
818.4 in²
Step-by-step explanation:
The area (A) of the shaded region is
A = area of circle - ( area of white sector + area of triangle )
= ( π × 27.8²) - (π × 27.8² × 
+(0.5 × 27.8 ×27.8 × sin150°)
= 2427.95 - (1416.30 + 193.21 )
= 2427.95 - 1609.51 ≈ 818.4 in²
Answer:
x = 2/3, -2/3
Step-by-step explanation:
Solve the equation for x by finding a
, b
, and c of the quadratic then apply the quadratic formula.
