The answer is 11/36
2/12 chance of rolling fours
because there are 2 sides containing a four on both dice combined and 12 sides in total.
Doubles mean you have to roll the same number simultaneously so let’s say we want to calculate the probability for double ones: then it’s 1/6 on the first dice for a one, and 1/6 on the second dice to land on a one as well.
I personally like to imagine a box like this:
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If you have one dice then it’s just a random segment on one of the lines. If you want the specific result from two dice then you want two specific segments which is also the 1 specific tile out of 36 (6 width times 6 height). So you multiply.
1/6 * 1/6 = 1/36 chance to roll double of ones
And 1/36 chance to roll double twos, threes, fours, fives, and sixes. But we don’t count the double fours because any four will do. So:
1/36 * 5 = 5/36
So for the probability of either doubles or containing a four is the probability of doubles of either number plus the probability of either dice being a four:
5/36 + 2/12 =
5/36 + 6/36 =
11/36
9514 1404 393
Answer:
11.6 cm
Step-by-step explanation:
As the page title tells you, the Pythagorean theorem must be applied more than once. As you know, it tells you the square of the hypotenuse is the sum of the squares of the two sides.
AD² = ED² +EA²
EA² = AD²-ED² = 7² -6² = 13
EA = √13 ≈ 3.606
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CD² = ED² +EC²
EC² = CD² -ED² = 10² -6² = 64
EC = √64 = 8
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The length of the horizontal diagonal is ...
AC = EA +EC = 3.6 +8 = 11.6 . . . cm
Answer:
1.88 pounds
Step-by-step explanation:
First, find the total amount of sugar, since there were 2 shipments
22.56(2)
= 45.12
Then, divide this by 24:
45.12/24
= 1.88
So, each canister had 1.88 pounds of sugar
Assume that,
adult = x
child = y
x+2y = 35 (1st equation)
2x+3y = 60 (2nd equation)
x = 35-2y (3rd equation)
Substitute 3 into 2 :
2(35-2y) + 3y =60
70-4y +3y = 60
y = 10
x+2y = 35
x+2(10) =35
x +20 =35
x = 15
One adult = $15
The Greatest Common Factor (GCF) is the largest number that will be divided evenly into that number. For example, for 24, the GCF is 12. For a polynomial, the GCF is the largest polynomial<span> that will divide evenly into that polynomial.</span>