Summation of 3n + 2 from n = 1 to n = 14 = (3(1) + 2) + (3(2) + 2) + (3(3) + 2) + . . . + (3(14) + 2) = 5 + 8 + 11 + ... + 44 ia an arithmetic progression with first term (a) = 5, common difference (d) = 3 and last term (l) = 44 and n = 14
Sn = n/2(a + l) = 14/2(5 + 44) = 7(49) = 343
Therefore, the required summation is 343.
.27 repeating.... you have to put three on the inside and 11 outside, so 11 goes into 3 zero times so put a zero at the top. Write a zero underneath and subtract 3-0 (obviously 3) and put a decimal point after the first three under the sign and the 0 above it. Add a zero after the threes decimal, and carry it down to the bottom most 3 to have 30. 11 goes into 30 two times so write a 2 at the top. Subtract the 30-22 at the bottom and get 8. Add another 0 after the 3 ( so now 3.00) and carry it to the 8 (80). 11 goes in 7 times, 77. So 7 on top and 80-77= 3 below. Add another zero to repeat process if necessary, but otherwise it repeats, just so you know ;) hope this helps
1200 = 100%
35% of 1200 = 420
1200 + 420 = 1620
There are 1620 students enrolled this year.
Answer:
g(x)=|x|
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Answer:
thanks
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