If a sphere is 120 feet in diameter what is the volume? Help please

Is 6 a factor of 30 true or false

beks73 [17]

true 6x5=30 15x2=30 so forth

6 0

3 years ago

Read 2 more answers

Use the function f(x)=x^2-8 find the inverse of f(x)

likoan [24]

Answer:

Step-by-step explanation:

let : y = x² - 8

calculate : x

x² = y + 8

x exist : y + 8 ≥ 0

x = √(y + 8) or x = - √(y + 8)

conclusion :

if : x ≥ 0 the inverse of f(x) is : g(x) = √(x + 8)

if : x ≤ 0 the inverse of f(x) is : h(x) = - √(x + 8)

4 0

3 years ago

Wha) is the image of the point (9,2) after a rotation of 90° counterclockwise about the origin?

ElenaW [278]

Given the point:

(x, y) ==> (9, 2)

Let's find the new point of the image after a rotation of 90 degrees counterclockwise about the origin.

To find the image of the point after a rotation of 90 degrees counterclockwise, apply the rules of rotation.

After a rotation of 90 degrees counterclockwise, the point (x, y) changes to (-y, x)

Thus, we have the point after the rotation:

(x, y) ==> (-y, x)

(9, 2) ==> (-2, 9)

Therefore, the image of the points after a rotation of 90 degrees counterclockwise is:

(-2, 9)

ANSWER:

(-2, 9)

5 0

11 months ago

F(x) = -322 Find f(-2)

serg [7]

Answer:

f ( - 2 ) = - 12

Step-by-step explanation:

f ( - 2 ) = - 3 ( -2 )^2

then you do the exponent first so

- 3 ( 4 )

now you multpily the - 3 and 4

you get - 12

8 0

2 years ago

Change the subject of the formula L = v 4kt - p to k.

Romashka [77]

Answer:

$\boxed{k = \frac{L^2 + p}{4t}}$

General Formulas and Concepts:

Algebra I

Basic Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Step-by-step explanation:

Step 1: Define

Identify given.

$\displaystyle L = \sqrt{4kt - p}$

Step 2: Solve for k
We can use equality properties to help us rewrite the equation to get k as our subject:

Let's first square both sides:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\\end{aligned}$

Next, add p to both sides:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\\end{aligned}$

Next, divide 4t by both sides:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\& \rightarrow \frac{L^2 + p}{4t} = k \\\end{aligned}$

We can rewrite the new equation by swapping sides to obtain our final expression:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow \boxed{k = \frac{L^2 + p}{4t}}\end{aligned}$

∴ we have changed the subject of the formula.

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Learn more about Algebra I: brainly.com/question/27698547

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Topic: Algebra I

6 0

2 years ago