Question

Simplify -8y^3(7y^2-4y-1) PLEASE HELP

Answer 1

Hey!

Alright, according to P.E.M.D.A.S., the first step to solving this expression is to distribute.

Original Expression :

$\displaystyle\ -8y^{3} (7y^{2} -4y-1)$

New Expression {Distributed Old Expression} :

$\displaystyle\ -(56y^{5} -32y^{4} -8y^{3} )$

Now all you have to do is simplify the parenthesis.

Old Expression :

$\displaystyle\ -(56y^{5} -32y^{4} -8y^{3} )$

New Expression {Simplified} :

$\displaystyle\ -56y^{5} + 32y^{4} + 8y^{3}$

So, since the expression can no longer be simplified, the final answer is...

$\displaystyle\ -56y^{5} + 32y^{4} + 8y^{3}$

Hope this helps!

- Lindsey Frazier ♥

Answer 2

Solution :

Given expression $-8y^{3}(7y^{2}-4y-1)$

To simplify this expression, first we need to know about the Distributive property.

Distributive Property: $a\times(b+c+d)=(a\times b)+(a\times c)+(a\times d)$

Given expression $-8y^{3}(7y^{2}-4y-1)$

Applying Distributive property on this expression:

$\Rigtharrow -8y^{3}(7y^{2}-4y-1)=((-8y^{3})\times7y^{2})+((-8y^{3})\times(-4y))+((-8y^{3})\times(-1))$

                           $= -56y^{5}+32y^{4}+8y^{3}$

Hence, the simplified form of the expression  $-8y^{3}(7y^{2}-4y-1)$ is  $-56y^{5}+32y^{4}+8y^{3}$.