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Otrada [13]
3 years ago
11

The area if a rectangle is 48 square centimeters. The lenght of the rectangle is 8 centimitwrs longer than the witch. Which equa

tion modles this situation
Mathematics
1 answer:
Pie3 years ago
4 0

So, The length is 8 cm longer than the width.


Area of a rectangle = l *w

48 cm^2 = l *w


l = w+8

48 cm^2 = w * w+8


48 = w^2 +8w

^ that's the equation that models it.  Or any other one listed

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\bf \stackrel{\textit{using elimination}}{ \begin{array}{llll} 3x+2y=42&\times -1\implies &\begin{matrix} -3x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~-2y=&-42\\ 3x+8y-72 &&~~\begin{matrix} 3x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~+8y=&72\\ \cline{3-4}\\ &&~\hfill 6y=&30 \end{array}} \\\\\\ y=\cfrac{30}{6}\implies \blacktriangleright y=5 \blacktriangleleft \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{substituting \underline{y} on the 1st equation}~\hfill }{3x+2(5)=42\implies 3x+10=42}\implies 3x=32 \\\\\\ x=\cfrac{32}{3}\implies \blacktriangleright x=10\frac{2}{3} \blacktriangleleft \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \left(10\frac{2}{3}~~,~~5 \right)~\hfill

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