It appears that you have a derivative and want to integrate...
dy/dx=1+3√x
y(x)=x+(2/3)x^(3/2)+C you are given that f(4)=25 so we can solve for the constant of integration...
y(4)=25=4+16/3+C
21=16/3+C
(63-16)/3=C
47/3=C so
f(x)=x+(2/3)x^(3/2)+47/3
f(x)=(3x+2x^(3/2)+47)/3
The correct answer is {1, 2, 5, 6}.
A intersect B would be {3, 4}; the complement of this is everything else.
Answer:
y= -2x + 12
Step-by-step explanation:
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Answer:
y = 8•6^x
Step-by-step explanation:
Here, we want to write an exponential equation
To fully write this, we need the values of a and b
From the first coordinates given;
8 = a•b^0
a = 8 since b^0 = 1
Furthermore;
288 = 8•b*2
b^2 = 36
b = √36
b = 6
So we have ;
y = 8•6^x
