6^2 = 36 is a perfect square.
Answer:
Step-by-step explanation:
The question is not terrifically worded. What it means is "What is the y value when x = 8" That's what f(8) conveys to you.
The answer (though zero is not marked and should be) is 1 unit above 0.
The answer is f(8) = 1 He's heading back.
Answer:
x = 0, y = 1
Step-by-step explanation:
2x + 6y = 6 → (1)
x - 3y = - 3 ( add 3y to both sides )
x = 3y - 3 → (2)
substitute x = 3y - 3 into (1)
2(3y - 3) + 6y = 6 ← distribute parenthesis and simplify left side
6y - 6 + 6y = 6
12y - 6 = 6 ( add 6 to both sides )
12y = 12 ( divide both sides by 12 )
y = 1
substitute y = 1 into (2)
x = 3(1) - 3 = 3 - 3 = 0
solution is x = 0 , y = 1
Answer:
b=20 or b=-20
Step-by-step explanation:
Keep in mind the meanings of the values of the discriminant:
If b^2-4ac=0, then the quadratic will have only 1 solution (double root)
If b^2-4ac<0, then the quadratic will have no real solutions
If b^2-4ac>0, then the quadratic will have 2 unique solutions
In this case, to get one real solution, the discriminant must be set up as b^2-4ac=0. Setting up the equation we get:
b^2-4(4)(25)=0
b^2-400=0
b^2=400
b=20 or b=-20
So the values of b would have to be either 20 or -20
