The number of minutes that would pass before they were 1870 feet apart is 5.47 minutes
- Since one student runs at a speed of 180 feet per minutes, in time t minutes, he moves a distance of d = 180t.
- Also, the second student runs at a speed of 160 feet per minute, in time t minutes, he moves a distance of d' = 160t.
Since they are initially 10 feet apart, their total distance apart after t minutes is D = d + 10 + d'
D = 180t + 10 + 160t
D = 340t + 10
<h3>Number of minutes before they are 1870 feet</h3>
Making t subject of the formula, we have
t = (D - 10)/340
Since they are 1870 feet apart after t minutes, D = 1870 feet.
t = (D - 10)/340
t = (1870 - 10)/340
t = 1860/340
t = 5.47 minutes
So, the number of minutes that would pass before they were 1870 feet apart is 5.47 minutes
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Answer:
and 
(with arrows on top)
Step-by-step explanation:
The sides of any angle are rays. This are half lines, which in your case both start at the point T, and one goes towards point U, while the other one goes from toward point S. So I would write TU (with a little arrow symbol on top). and in the other box I would write TS also with a little arrow symbol on top.
The answer would be True. It is NOT.
-x/2 + 4 > = 6
-x/2 > = 6 - 4
-x/2 > = 2...multiply both sides by -2
x < = -4
_________________________________________
x + 3/2 < 7/4
x < 7/4 - 3/2
x < 7/4 - 6/4
x < 1/4
Answer: 1.5 tons
Step-by-step explanation:
Given
The recycling center collected 48,000 ounces of aluminum can
An ounce is the unit of weight and it can be expressed in tons as
