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Stels [109]
3 years ago
13

a recipe calls for 5/8 cups of butter. Angie wants to triple the recipe but she has only 1 7/8 cups of butter

Mathematics
1 answer:
attashe74 [19]3 years ago
7 0
She needs 3 * 5/8 = 15/8  = 1  7/8 cups of butter

So she has enough already.
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Suppose the number of gallons of gasoline per day used by a car is normally distributed with a mean of 2.2 gallons and a standar
const2013 [10]
The difference in gallons per day used is 3.6.

The formula to calculate a z-score is:
z=\frac{X-\mu}{\sigma},

where X is the value used to calculate the score, μ is the mean and σ is the standard deviation.  We have the z-scores so we must work backward:

3=\frac{X-2.2}{1.2}\text{ and }0=\frac{X-2.2}{1.2}

For both equations, we will cancel the 1.2 by multiplying both sides:
3\times1.2=(\frac{X-2.2}{1.2})\times1.2\text{ and }0\times1.2=(\frac{X-2.2}{1.2})\times1.2
\\
\\3.6=X-2.2\text{ and }0=X-2.2

Now we will cancel 2.2 from both equations by adding it to both sides:

3.6+2.2=X-2.2+2.2     and       0+2.2=X-2.2+2.2
5.8=X     and       2.2=X

The difference in gas used per day would be given by
5.8-2.2 = 3.6.
5 0
3 years ago
S - 1/3 equals 4/9 so S equals what?
bekas [8.4K]
s -  \frac{1}{3} =  \frac{4}{9} \\ \\ s =  \frac{4}{9} +  \frac{1}{3} \\ \\ s =  \frac{7}{9} \\ \\ Answer: \fbox {s = 7/9} \ or \ \fbox {s = 0.7778}
5 0
3 years ago
This year the CDC reported that 30% of adults received their flu shot. Of those adults who received their flu shot,
Vlad [161]

Using conditional probability, it is found that there is a 0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.

Conditional Probability

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem:

  • Event A: Person has the flu.
  • Event B: Person got the flu shot.

The percentages associated with getting the flu are:

  • 20% of 30%(got the shot).
  • 65% of 70%(did not get the shot).

Hence:

P(A) = 0.2(0.3) + 0.65(0.7) = 0.515

The probability of both having the flu and getting the shot is:

P(A \cap B) = 0.2(0.3) = 0.06

Hence, the conditional probability is:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.06}{0.515} = 0.1165

0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.

To learn more about conditional probability, you can take a look at brainly.com/question/14398287

7 0
2 years ago
L
d1i1m1o1n [39]

Whole numbers

Natural numbers

Real nunbers

6 0
3 years ago
What is 10.9091% to 2 decimal places
Tom [10]

Answer:

10.91%

Step-by-step explanation:

Take your number: 10.9091

Now find the first 3 decimals: 10.<u>909</u>

If the last (3rd) decimal is 5 or more raise the 2nd decimal: 10.9<u>09</u> → 10.9<u>1</u>

That is 2 decimal places

(if your teacher doesn't want it rounded then just 10.90%)

4 0
3 years ago
Read 2 more answers
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